Pertanyaan

Nilai dari x → ∞ lim ( 3 x 4 − 5 x 2 + 4 6 x 4 + 7 x 3 − 8 ) adalah ...

Nilai dari $x \to \infty lim (\frac{6 x ^{4} + 7 x ^{3} - 8}{3 x ^{4} - 5 x ^{2} + 4})$ adalah ...

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B

Pembahasan

Jadi, jawaban yang tepat adalah B

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of fraction numerator 6 x to the power of 4 plus 7 x cubed minus 8 over denominator 3 x to the power of 4 minus 5 x squared plus 4 end fraction end cell equals cell limit as x rightwards arrow infinity of fraction numerator 6 x to the power of 4 plus 7 x cubed minus 8 over denominator 3 x to the power of 4 minus 5 x squared plus 4 end fraction cross times fraction numerator begin display style 1 over x to the power of 4 end style over denominator begin display style 1 over x to the power of 4 end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of fraction numerator begin display style fraction numerator 6 x to the power of 4 over denominator x to the power of 4 end fraction end style plus begin display style fraction numerator 7 x cubed over denominator x to the power of 4 end fraction end style minus begin display style 8 over x to the power of 4 end style over denominator begin display style fraction numerator 3 x to the power of 4 over denominator x to the power of 4 end fraction end style minus begin display style fraction numerator 5 x squared over denominator x to the power of 4 end fraction end style plus begin display style 4 over x to the power of 4 end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of fraction numerator begin display style 6 plus 7 over x minus 8 over x to the power of 4 end style over denominator begin display style 3 minus 5 over x squared plus 4 over x to the power of 4 end style end fraction end cell row blank equals cell fraction numerator begin display style 6 plus 7 over infinity minus 8 over infinity end style over denominator begin display style 3 minus 5 over infinity plus 4 over infinity end style end fraction end cell row blank equals cell fraction numerator begin display style 6 plus 0 minus 0 end style over denominator begin display style 3 minus 0 plus 0 end style end fraction end cell row blank equals cell 6 over 3 end cell row blank equals 2 end table$

Jadi, jawaban yang tepat adalah B