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Pertanyaan

Nilai x → − 1 lim ​ ( 7 + x ​ − 5 − x ​ 3 x + 3 ​ ) adalah ...

Nilai  adalah ...

  1. begin mathsize 14px style 6 square root of 8 end style 

  2. size 14px 6 square root of size 14px 6 

  3. 3 square root of size 14px 8 

  4. 3 square root of size 14px 6 

  5. begin mathsize 14px style 2 square root of 6 end style 

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E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

Pembahasan

Dengan metode mengalikan bentuk sekawannya Jadi, jawaban yang tepat adalah D.

Dengan metode mengalikan bentuk sekawannya

begin mathsize 14px style table attributes columnalign center left columnspacing 2px end attributes row blank cell limit as straight x rightwards arrow negative 1 of left parenthesis fraction numerator 3 straight x plus 3 over denominator square root of 7 plus straight x end root minus square root of 5 minus straight x end root end fraction right parenthesis end cell row equals cell limit as straight x rightwards arrow negative 1 of left parenthesis fraction numerator 3 straight x plus 3 over denominator square root of 7 plus straight x end root minus square root of 5 minus straight x end root end fraction cross times fraction numerator square root of 7 plus straight x end root plus square root of 5 minus straight x end root over denominator square root of 7 plus straight x end root plus square root of 5 minus straight x end root end fraction right parenthesis end cell row equals cell limit as straight x rightwards arrow negative 1 of open parentheses fraction numerator open parentheses 3 straight x plus 3 close parentheses open parentheses square root of 7 plus straight x end root plus square root of 5 minus straight x end root close parentheses over denominator 7 plus straight x minus open parentheses 5 minus straight x close parentheses end fraction close parentheses end cell row equals cell limit as straight x rightwards arrow negative 1 of open parentheses fraction numerator open parentheses 3 straight x plus 3 close parentheses open parentheses square root of 7 plus straight x end root plus square root of 5 minus straight x end root close parentheses over denominator 2 plus 2 straight x end fraction close parentheses end cell row equals cell limit as straight x rightwards arrow negative 1 of open parentheses fraction numerator 3 up diagonal strike open parentheses straight x plus 1 close parentheses end strike open parentheses square root of 7 plus straight x end root plus square root of 5 minus straight x end root close parentheses over denominator 2 up diagonal strike open parentheses 1 plus straight x close parentheses end strike end fraction close parentheses end cell row equals cell fraction numerator 3 open parentheses square root of 7 plus open parentheses negative 1 close parentheses end root plus square root of 5 minus open parentheses negative 1 close parentheses end root close parentheses over denominator 2 end fraction end cell row equals cell fraction numerator 3 open parentheses square root of 6 plus square root of 6 close parentheses over denominator 2 end fraction end cell row equals cell fraction numerator 3 times up diagonal strike 2 square root of 6 over denominator up diagonal strike 2 end fraction end cell row equals cell 3 square root of 6 end cell end table end style 

Jadi, jawaban yang tepat adalah D.

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