Nilai x→6lim 12−2x6x−36=...

Pertanyaan

Nilai $begin mathsize 14px style limit as x rightwards arrow 6 of space fraction numerator 6 x minus 36 over denominator 12 minus 2 x end fraction equals end style$ ...

S. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Prof. DR. Hamka

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

Pembahasan

Gunakan pemfaktoran untuk mengetahui nilai limit seperti berikut:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 6 of space fraction numerator 6 x minus 36 over denominator 12 minus 2 x end fraction end cell equals cell limit as x rightwards arrow 6 of space fraction numerator negative 3 open parentheses negative 2 x plus 12 close parentheses over denominator 12 minus 2 x end fraction end cell row blank equals cell limit as x rightwards arrow 6 of space fraction numerator negative 3 down diagonal strike open parentheses 12 minus 2 x close parentheses end strike over denominator down diagonal strike 12 minus 2 x end strike end fraction end cell row blank equals cell limit as x rightwards arrow 6 of space minus 3 end cell row blank equals cell negative 3 end cell end table end style$

Nilai $begin mathsize 14px style limit as x rightwards arrow 6 of space fraction numerator 6 x minus 36 over denominator 12 minus 2 x end fraction equals negative 3 end style$ .

Jadi, jawaban yang tepat adalah D.