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Luas daerah yang dibatasi oleh kurva dan sumbu X, garis x=2 dan garis x=4 adalah ...

Luas daerah yang dibatasi oleh kurva y equals x squared minus 2 x dan sumbu X, garis x=2 dan garis x=4 adalah ...

 

  1. 10 over 2 s a t u a n space l u a s

  2. fraction numerator begin display style 18 end style over denominator begin display style 2 end style end fraction s a t u a n space l u a s

  3. fraction numerator begin display style 20 end style over denominator begin display style 3 end style end fraction s a t u a n space l u a s

  4. fraction numerator begin display style 26 end style over denominator begin display style 3 end style end fraction s a t u a n space l u a s

  5. fraction numerator begin display style 31 end style over denominator begin display style 3 end style end fraction s a t u a n space l u a s

Jawaban:

P e r h a t i k a n space g a m b a r space y a n g space t e r b e n t u k space o l e h space k u r v a space y equals x squared minus 2 x comma s u m b u minus X comma g a r i s space x equals 2 space d a n space g a r i s space x equals 4 b e r i k u t.

D a r i space g a m b a r space t e r l i h a t space L u a s space d a e r a h space y a n g space a k a n space d i c a r i space b e r a d a space d i space a t a s space s u m b u minus X comma space m a k a space L u a s n y a  L equals integral subscript 2 superscript 4 left parenthesis x squared minus 2 x right parenthesis d x  equals open square brackets 1 third x cubed minus x squared close square brackets subscript 2 to the power of 4  equals open square brackets 1 third left parenthesis 4 right parenthesis cubed minus left parenthesis 4 right parenthesis squared close square brackets minus open square brackets 1 third left parenthesis 2 right parenthesis cubed minus left parenthesis 2 right parenthesis squared close square brackets  equals 64 over 3 minus 16 minus 8 over 3 plus 4  equals 20 over 3  M a k a space l a s space d a e r a h space t e r s e b u t space a d a l a h space 20 over 3 space s a t u a n space l u a s

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