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Pertanyaan

Luas daerah yang dibatas oleh kurva y = x2 – 2x, sumbu X, garis x = 2, dan garis x = 3 adalah ...

  1. 1 over 6 space s a t u a n space l u a s

  2. 1 third space s a t u a n space l u a s

  3. 2 over 3 space s a t u a n space l u a s

  4. 4 over 3 space s a t u a n space l u a s

  5. 3 over 2 space s a t u a n space l u a s

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

J i k a space i n g i n space m e n g g a m b a r space g r a f i k n y a space d u l u space d e m i k i a n space c a r a n y a colon  T e m u k a n space p e m b u a t space n o l n y a space d u l u comma space d e n g a n space d i f a k t o r k a n.  x squared minus 2 x equals 0  x left parenthesis x minus 2 right parenthesis equals 0  x equals 0 logical or x equals 2  J a d i space s a a t space space y space equals space 0 comma d i d a p a t space t i t i k minus t i t i k space left parenthesis 0 comma 0 right parenthesis space d a n space left parenthesis 2 comma 0 right parenthesis.  T i t i k space p u n c a k n y a space s a a t colon  x space equals fraction numerator space space minus b over denominator 2 a end fraction space space equals 2 over 2 space space equals space 1    J a d i  y subscript m a k s end subscript equals 1 squared minus 2 left parenthesis 1 right parenthesis equals negative 1  T i t i k space p u n c a k n y a space k e t e m u space left parenthesis 1 comma space minus space 1 space right parenthesis  P e r h a t i k a n space g r a f i k space b e r i k u t colon

L u a s space d a e r a h space y a n g space d i i n g i n k a n space s o a l space y a i t u  L equals integral subscript 2 superscript 3 left parenthesis x squared minus 2 x right parenthesis d x  L equals open square brackets 1 third x cubed minus x squared close square brackets subscript 2 superscript 3 space space space  L equals open parentheses 1 third.3 cubed minus 3 squared close parentheses minus open parentheses 1 third.2 cubed minus 2 squared close parentheses    L equals left parenthesis 0 right parenthesis minus open parentheses 8 over 3 minus 4 space space close parentheses  L equals 4 over 3 space s a t u a n space l u a s

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Gambarlah dan hitunglah luas daerah-daerah tertutup yang dibatasi oleh kurva-kurva berikut : d. y=sinxdany=cosxpadainterval[0,2π]

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