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Lingkaran L : ( x + 1 ) 2 + ( y − 2 ) 2 = 1 dirotasikan sebesar 90° terhadap titik pusat (0, 0). Kemudian direfleksikan terhadap sumbu X. Persamaan lingkaran hasil transformasi lingkaran L adalah...

Lingkaran dirotasikan sebesar 90° terhadap titik pusat (0, 0). Kemudian direfleksikan terhadap sumbu X. Persamaan lingkaran hasil transformasi lingkaran L adalah...

  1. size 14px left parenthesis size 14px x size 14px space size 14px minus size 14px space size 14px 1 size 14px space size 14px right parenthesis to the power of size 14px 2 size 14px space size 14px plus size 14px space size 14px left parenthesis size 14px y size 14px space size 14px minus size 14px space size 14px 2 size 14px right parenthesis to the power of size 14px 2 size 14px equals size 14px space size 14px 1

  2. begin mathsize 14px style left parenthesis x space minus space 1 space right parenthesis squared space plus space left parenthesis y space plus space 2 right parenthesis squared equals space 1 end style

  3. size 14px left parenthesis size 14px x size 14px space size 14px plus size 14px space size 14px 2 size 14px space size 14px right parenthesis to the power of size 14px 2 size 14px space size 14px plus size 14px space size 14px left parenthesis size 14px y size 14px space size 14px plus size 14px space size 14px 1 size 14px right parenthesis to the power of size 14px 2 size 14px equals size 14px space size 14px 1

  4. size 14px left parenthesis size 14px x size 14px space size 14px minus size 14px space size 14px 2 size 14px space size 14px right parenthesis to the power of size 14px 2 size 14px space size 14px plus size 14px space size 14px left parenthesis size 14px y size 14px space size 14px minus size 14px space size 14px 1 size 14px right parenthesis to the power of size 14px 2 size 14px equals size 14px space size 14px 1

  5. size 14px left parenthesis size 14px x size 14px space size 14px plus size 14px space size 14px 2 size 14px space size 14px right parenthesis to the power of size 14px 2 size 14px space size 14px plus size 14px space size 14px left parenthesis size 14px y size 14px space size 14px minus size 14px space size 14px 1 size 14px right parenthesis to the power of size 14px 2 size 14px equals size 14px space size 14px 1

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M. Alfi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

persamaan lingkaran hasil transformasi adalah E.

persamaan lingkaran hasil transformasi adalah E. begin mathsize 14px style begin bold style left parenthesis x plus 2 right parenthesis end style to the power of bold 2 bold plus begin bold style left parenthesis y minus 1 right parenthesis end style to the power of bold 2 bold equals bold 1 end style 

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Pembahasan

Pemetaan terhadap Pemetaan terhadap garis Sumbu Jadi, persamaan lingkaran hasil transformasi adalah E.

Pemetaan terhadap begin mathsize 14px style 90 degree end style 

begin mathsize 14px style open parentheses x comma blank y close parentheses rightwards arrow open parentheses negative y apostrophe comma blank x apostrophe close parentheses end style

Pemetaan terhadap garis  Sumbu begin mathsize 14px style X end style

begin mathsize 14px style left parenthesis x comma y right parenthesis rightwards arrow left parenthesis x comma negative y right parenthesis left parenthesis negative y apostrophe comma x apostrophe right parenthesis rightwards arrow left parenthesis negative y comma negative x right parenthesis end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis x plus 1 right parenthesis squared plus left parenthesis y minus 2 right parenthesis squared end cell equals 1 row cell left parenthesis negative y plus 1 right parenthesis squared plus left parenthesis negative x minus 2 right parenthesis squared end cell equals 1 row cell left parenthesis y minus 1 right parenthesis squared plus left parenthesis x plus 2 right parenthesis squared end cell equals 1 end table end style

Jadi, persamaan lingkaran hasil transformasi adalah E. begin mathsize 14px style begin bold style left parenthesis x plus 2 right parenthesis end style to the power of bold 2 bold plus begin bold style left parenthesis y minus 1 right parenthesis end style to the power of bold 2 bold equals bold 1 end style 

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Tentukan bayangan dari segitiga ABC dengan A ( 2 , 1 ) , B ( 6 , 1 ) dan C ( 2 , 5 ) jika diputar 9 0 ∘ dengan pusat ( 0 , 0 ) lalu dicerminkan terhadap sumbu x , kemudian digeser ( − 2 − 3 ​ ) !

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