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Larutan garam  0,05 M mempunyai pH 5+log 2, harga ...

Larutan garam begin mathsize 14px style N H subscript 4 C I end style 0,05 M mempunyai pH 5+log 2, harga begin mathsize 14px style K subscript b space N H subscript 3 end style tersebut adalah ...

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell pH space end cell equals cell space 5 plus log space 2 end cell row cell pH space end cell equals cell space 5 space minus sign space log space 1 half end cell end table end style  

Sehingga nilai begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell pH space end cell equals cell space minus sign space log space open square brackets H to the power of plus sign close square brackets end cell row cell 5 space minus sign space log space 1 half space end cell equals cell space minus sign space log space open square brackets H to the power of plus sign close square brackets end cell row cell negative sign space log space 0 comma 5 cross times 10 to the power of negative sign 5 end exponent space end cell equals cell space minus sign space log space open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets space end cell equals cell space 0 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets space end cell equals cell space 5 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

Menentukan nilai begin mathsize 14px style K subscript b space N H subscript 3 end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets space end cell equals cell space square root of K subscript w over K subscript b cross times M end root end cell row cell 5 cross times 10 to the power of negative sign 6 end exponent space end cell equals cell space square root of 10 to the power of negative sign 14 end exponent over K subscript b cross times 0 comma 05 end root end cell row cell open parentheses 5 cross times 10 to the power of negative sign 6 end exponent close parentheses squared space end cell equals cell space 10 to the power of negative sign 14 end exponent over K subscript b cross times 0 comma 05 end cell row cell 25 cross times 10 to the power of negative sign 12 end exponent space end cell equals cell space fraction numerator 5 cross times 10 to the power of negative sign 16 end exponent over denominator K subscript b end fraction end cell row cell K subscript b space end cell equals cell space fraction numerator 5 cross times 10 to the power of negative sign 16 end exponent over denominator 25 cross times 10 to the power of negative sign 12 end exponent end fraction end cell row cell K subscript b space end cell equals cell space 2 cross times 10 to the power of negative sign 5 end exponent end cell end table end style 

Jadi, jawaban yang benar adalah begin mathsize 14px style K subscript italic b bold space N H subscript bold 3 bold space bold equals bold space bold 2 bold cross times bold 10 to the power of bold minus sign bold 5 end exponent end style.

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