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Larutan N2​H5​Cl 0,5 M memiliki pH = 4,27. Berapakah tetapan kesetimbangan hidrolisis garam ini?

Pertanyaan

Larutan N subscript 2 H subscript 5 Cl 0,5 M memiliki pH = 4,27. Berapakah tetapan kesetimbangan hidrolisis garam ini?

Q. 'Ainillana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Jawaban

 tetapan kesetimbangan hidrolisis garam N subscript 2 H subscript 5 Cl adalah 7 comma 2 cross times 10 to the power of negative sign 9 end exponent.

Pembahasan

Hidrolisis garam adalah reaksi antara air dan ion-ion yang berasal dari asam lemah atau basa lemah suatu garam.

N subscript 2 H subscript 5 Cl merupakan garam asam yang terdiri dari basa lemah (kation) dan asam kuat (anion), reaksi ionisasi garam sebagai berikut:

 N subscript 2 H subscript 5 Cl yields N subscript 2 H subscript 5 to the power of plus plus Cl to the power of minus sign   

Dengan demikian, open square brackets N subscript 2 H subscript 5 Cl close square brackets equals open square brackets N subscript 2 H subscript 5 to the power of plus close square brackets equals 0 comma 5 space M.

Data pH dapat diubah menjadi nilai H to the power of plus sign berikut:

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 4 comma 27 end cell row blank equals cell 5 minus sign 0 comma 73 end cell row blank equals cell 5 minus sign log space 6 end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 6 cross times 10 to the power of negative sign 5 end exponent end cell end table  

Sehingga konsentrasi N subscript 2 H subscript 5 Cl dapat dicari menggunakan persamaan:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript h cross times open square brackets N subscript 2 H subscript 5 to the power of plus close square brackets end root end cell row cell 6 cross times 10 to the power of negative sign 5 end exponent end cell equals cell square root of K subscript h cross times open square brackets 0 comma 5 close square brackets end root space left parenthesis kuadratkan space kedua space ruas right parenthesis end cell row cell open parentheses 6 cross times 10 to the power of negative sign 5 end exponent close parentheses squared end cell equals cell open parentheses square root of K subscript h cross times open square brackets 0 comma 5 close square brackets end root close parentheses squared end cell row cell 36 cross times 10 to the power of negative sign 10 end exponent end cell equals cell K subscript h cross times open square brackets 0 comma 5 close square brackets end cell row cell K subscript h end cell equals cell fraction numerator 36 cross times 10 to the power of negative sign 10 end exponent over denominator 0 comma 5 end fraction end cell row blank equals cell 72 cross times 10 to the power of negative sign 10 end exponent end cell row blank equals cell 7 comma 2 cross times 10 to the power of negative sign 9 end exponent end cell end table  

Jadi tetapan kesetimbangan hidrolisis garam N subscript 2 H subscript 5 Cl adalah 7 comma 2 cross times 10 to the power of negative sign 9 end exponent.

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