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Larutan amoniak 0,4 M memiliki pH = 11 + log 2. Be...

Larutan amoniak 0,4 M memiliki pH = 11 + log 2. Berapa pH larutan 0,1 M begin mathsize 14px style N H subscript 4 Br end style ....

Jawaban:

begin mathsize 14px style pOH space equals 14 minus sign pH pOH equals 14 minus sign open parentheses 11 plus log space 2 close parentheses pOH equals 3 minus sign log space 2  open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign pOH end exponent open square brackets O H to the power of minus sign close square brackets equals 2 cross times 10 to the power of negative sign 3 end exponent space M  open square brackets O H to the power of minus sign close square brackets equals square root of K subscript b cross times open square brackets N H subscript 3 close square brackets end root 2 cross times 10 to the power of negative sign 3 end exponent space M equals square root of K subscript b cross times open parentheses 0 comma 4 close parentheses end root K subscript b equals 10 to the power of negative sign 5 end exponent end style

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of K subscript italic w over K subscript italic b cross times open square brackets N H subscript 4 to the power of plus close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root open square brackets H to the power of plus sign close square brackets equals 10 to the power of negative sign 5 end exponent  pH space equals space minus sign log open square brackets H to the power of plus sign close square brackets pH equals 5 end style

Dengan demikian, maka jawaban yang tepat adalah 5.

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