RoboguruRoboguru
SD

Larutan 100 mL NH3​ 0,8 M dicampur dengan 100 mL HCl 0,8 M, menurut reaksi: NH3​(aq)+HCl(aq)→NH4​Cl(aq)(Kw=10−14, Kb NH3​=10−5). Harga pH larutan tersebut adalah ...

Pertanyaan

Larutan 100 mL N H subscript 3 0,8 M dicampur dengan 100 mL H C calligraphic l 0,8 M, menurut reaksi:

N H subscript 3 left parenthesis a q right parenthesis plus H C calligraphic l left parenthesis a q right parenthesis rightwards arrow N H subscript 4 C calligraphic l left parenthesis a q right parenthesis  left parenthesis K w equals 10 to the power of negative 14 end exponent comma space K b space N H subscript 3 equals 10 to the power of negative 5 end exponent right parenthesis.

Harga pH larutan tersebut adalah ...

  1. 5 - log 2

  2. 5 + log 2

  3. 9 - log 2

  4. 9 + log 2

  5. 12 + log 2

S. Susanti

Master Teacher

Mahasiswa/Alumni Universitas Jayabaya

Jawaban terverifikasi

Pembahasan

space space space space space space space space space space space space space space space space space space space space space space N H subscript 3 space space space space space space space space plus space space space space space space space space space H C calligraphic l space space space space space space space space space space rightwards arrow space space space space space space space space space space space space N H subscript 4 C calligraphic l space space space  M u l a space space space space space space space space space 80 space m m o l space space space space space space space space space space space space space 80 space m m o l  R e a k s i space space minus 80 space m m o l space space space space space space space space space minus 80 space m m o l space space space space space space space space space space space space space space space space space space space plus 80 space m m o l  S i s a space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 80 space m m o l    N H subscript 4 C calligraphic l equals fraction numerator m o l over denominator V subscript t o t a l end subscript end fraction equals fraction numerator 0 comma 08 space m o l over denominator 0 comma 2 space L end fraction equals 0 comma 4 space M    C H subscript 3 C O O K space m e r u p a k a n space g a r a m space b a s a comma space s e h i n g g a colon  left square bracket H to the power of plus right square bracket equals square root of fraction numerator K w cross times left square bracket g a r a m right square bracket over denominator K b end fraction end root equals square root of fraction numerator 10 to the power of negative 14 end exponent cross times left square bracket 0 comma 4 right square bracket over denominator 10 to the power of negative 15 end exponent end fraction end root equals square root of 4 cross times 10 to the power of negative 10 end exponent end root equals 2 cross times 10 to the power of negative 5 end exponent space M  p H space space equals negative log space 2 cross times 10 to the power of negative 5 end exponent equals 5 minus log space 2

28

0.0 (0 rating)

Pertanyaan serupa

Larutan NH3​ 0,2 M (Kb=1×10−5) sebanyak 50 mL ditambahkan ke dalam 50 mL larutan HCl 0,2 sehingga terjadi reaksi: NH3​(aq) + HCl (aq)→NH4​Cl (aq) (Kw=10−14). Harga pH larutan tersebut adalah ....

175

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia