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Larutan 100 mL N H 3 ​ 0,8 M dicampur dengan 100 mL H Cl 0,8 M, menurut reaksi: N H 3 ​ ( a q ) + H Cl ( a q ) → N H 4 ​ Cl ( a q ) ( K w = 1 0 − 14 , K b N H 3 ​ = 1 0 − 5 ) . Harga pH larutan tersebut adalah ...

Larutan 100 mL 0,8 M dicampur dengan 100 mL 0,8 M, menurut reaksi:

.

Harga pH larutan tersebut adalah ...

  1. 5 - log 2

  2. 5 + log 2

  3. 9 - log 2

  4. 9 + log 2

  5. 12 + log 2

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S. Susanti

Master Teacher

Mahasiswa/Alumni Universitas Jayabaya

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Pembahasan

space space space space space space space space space space space space space space space space space space space space space space N H subscript 3 space space space space space space space space plus space space space space space space space space space H C calligraphic l space space space space space space space space space space rightwards arrow space space space space space space space space space space space space N H subscript 4 C calligraphic l space space space  M u l a space space space space space space space space space 80 space m m o l space space space space space space space space space space space space space 80 space m m o l  R e a k s i space space minus 80 space m m o l space space space space space space space space space minus 80 space m m o l space space space space space space space space space space space space space space space space space space space plus 80 space m m o l  S i s a space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 80 space m m o l    N H subscript 4 C calligraphic l equals fraction numerator m o l over denominator V subscript t o t a l end subscript end fraction equals fraction numerator 0 comma 08 space m o l over denominator 0 comma 2 space L end fraction equals 0 comma 4 space M    C H subscript 3 C O O K space m e r u p a k a n space g a r a m space b a s a comma space s e h i n g g a colon  left square bracket H to the power of plus right square bracket equals square root of fraction numerator K w cross times left square bracket g a r a m right square bracket over denominator K b end fraction end root equals square root of fraction numerator 10 to the power of negative 14 end exponent cross times left square bracket 0 comma 4 right square bracket over denominator 10 to the power of negative 15 end exponent end fraction end root equals square root of 4 cross times 10 to the power of negative 10 end exponent end root equals 2 cross times 10 to the power of negative 5 end exponent space M  p H space space equals negative log space 2 cross times 10 to the power of negative 5 end exponent equals 5 minus log space 2

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Larutab HCl 0,8 M sebanyak 100 mL ditambahkan pada 100 mL larutan N H 3 ​ 0 , 8 M ( K b N H 3 ​ = 1 × 1 0 − 5 , K w = 1 0 − 14 ) menurut reaksi: N H 3 ​ ( a q ) + H Cl ( a q ) → N H 4 ​ Cl ( a q ) ...

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