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Jika panjang gelombang de Broglie sebuah elektron adalah space 6 comma 6 space text Å end text. Berapakah kecepatan dan energi kinetiknya? 

Y. Maghfirah

Master Teacher

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Pembahasan

Diketahui :

table attributes columnalign right center left columnspacing 0px end attributes row lambda equals cell space 6 comma 6 cross times 10 to the power of negative 10 end exponent space meter end cell row h equals cell 6 comma 63 cross times 10 to the power of negative 34 end exponent straight J times straight s end cell row m equals cell space 9 comma 11 cross times 10 to the power of negative 31 end exponent kg end cell row blank blank blank end table

Ditanyakan: v space d a n space E subscript k space ?

Penyelesaian :

Untuk menentukan kecepatan gunakan persamaan berikut:

table attributes columnalign right center left columnspacing 0px end attributes row lambda equals cell h over p end cell row blank equals cell fraction numerator h over denominator m times v end fraction end cell row blank blank blank row blank blank cell maka comma end cell row v equals cell fraction numerator h over denominator m times lambda end fraction end cell row blank equals cell space fraction numerator left parenthesis 6 comma 63 cross times 10 to the power of negative 34 end exponent straight J times straight s right parenthesis over denominator left parenthesis 9 comma 11 cross times 10 to the power of negative 31 end exponent kg right parenthesis times left parenthesis 6 comma 6 cross times 10 to the power of negative 10 end exponent straight m right parenthesis end fraction end cell row blank equals cell 11 cross times 10 to the power of 5 bevelled fraction numerator space straight m over denominator straight s end fraction end cell end table

kecepatan elektron adalah 11 cross times 10 to the power of 5 space bevelled straight m over straight s

sedangkan energi kinetiknya adalah :

table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript k end cell equals cell 1 half m times v squared end cell row blank equals cell space 1 half left parenthesis 9 comma 11 cross times 10 to the power of negative 31 end exponent space kg right parenthesis times left parenthesis 11 cross times 10 to the power of 5 space bevelled straight m over straight s right parenthesis squared end cell row blank equals cell 5 comma 51 cross times 10 to the power of negative 19 end exponent space straight J end cell end table

Dengan demikian, kecepatan elektron adalah bold 11 bold cross times bold 10 to the power of bold 5 bold space bold m bold divided by bold s dan energi kinetik elektronnya adalah  bold 5 bold comma bold 51 bold cross times bold 10 to the power of bold minus bold 19 end exponent bold space bold Joule.

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