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Jika energi kinetik sebuah elektron adalah 10,0 eV, berapakah panjang gelombang de Broglie elektron tersebut? (Tetapan Planck = 6,63×10−34 Js, muatan elektron = 1,6×10−34 C massa elektron = 9,11×10−31 kg.

Pertanyaan

Jika energi kinetik sebuah elektron adalah 10,0 eV, berapakah panjang gelombang de Broglie elektron tersebut? (Tetapan Planck = 6 comma 63 cross times 10 to the power of negative 34 end exponent space Js, muatan elektron = 1 comma 6 cross times 10 to the power of negative 34 end exponent space straight C massa elektron = 9 comma 11 cross times 10 to the power of negative 31 end exponent space kg.

  1. 4 comma 1 cross times 10 to the power of 16 space straight m 

  2. 3 comma 9 cross times 10 to the power of 10 space straight m 

  3. 5 comma 5 cross times 10 to the power of negative 10 end exponent space straight m space

  4. 2 comma 3 cross times 10 to the power of 14 space straight m 

  5. 4 comma 5 cross times 10 to the power of 14 space straight m 

J. Khairina

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

d i k e t a h u i colon E k equals 10 space e V h equals 6 comma 63 cross times 10 to the power of negative 34 end exponent q equals 1 comma 6 cross times 10 to the power of negative 19 end exponent space C m equals 9 comma 11 cross times 10 to the power of negative 31 end exponent space k g  d i tan y a colon space lambda ?  j a w a b colon E k equals 1 half m v squared 10 cross times 1 comma 6 cross times 10 to the power of negative 19 end exponent equals 1 half cross times 9 comma 11 cross times 10 to the power of negative 31 end exponent cross times v squared v equals 1 comma 8 cross times 10 to the power of 6 space end exponent space m divided by s  straight lambda equals straight h over mv straight lambda equals fraction numerator 6 comma 63 cross times 10 to the power of negative 34 end exponent over denominator 9 comma 11 cross times 10 to the power of negative 31 end exponent space cross times 1 comma 8 cross times 10 to the power of 6 space end exponent space end fraction straight lambda equals 3 comma 9 cross times 10 to the power of 10 space m

Jadi jawaban yang benar adalah B.

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