Pertanyaan

Jika x → a lim f ( x ) = − 2 , x → a lim g ( x ) = 4 , x → a lim h ( x ) = 13 . Nilai dari x → a lim h ( x ) 5 f ( x ) − ( g ( x ) ) 2 = ...

Jika $x \to a lim f (x) = - 2, x \to a lim g (x) = 4, x \to a lim h (x) = 13$ . Nilai dari $x \to a lim \frac{5 f ( x ) - ( g ( x ) ) ^{2}}{h ( x )} = ...$

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Jawaban terverifikasi

Jawaban

.

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow a of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 5 f open parentheses x close parentheses minus open parentheses g open parentheses x close parentheses close parentheses squared over denominator h open parentheses x close parentheses end fraction end cell end table equals negative 2$ .

Pembahasan

Jadi, .

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow a of f open parentheses x close parentheses end cell equals cell negative 2 end cell row cell f open parentheses a close parentheses end cell equals cell negative 2 end cell row cell limit as x rightwards arrow a of g open parentheses x close parentheses end cell equals 4 row cell g open parentheses a close parentheses end cell equals 4 row cell limit as x rightwards arrow a of h open parentheses x close parentheses end cell equals 13 row cell h open parentheses a close parentheses end cell equals 13 row cell limit as x rightwards arrow a of fraction numerator 5 f open parentheses x close parentheses minus open parentheses g open parentheses x close parentheses close parentheses squared over denominator h open parentheses x close parentheses end fraction end cell equals cell fraction numerator 5 f open parentheses a close parentheses minus open parentheses g open parentheses a close parentheses close parentheses squared over denominator h open parentheses a close parentheses end fraction end cell row blank equals cell fraction numerator 5 open parentheses negative 2 close parentheses minus open parentheses 4 close parentheses squared over denominator 13 end fraction end cell row blank equals cell fraction numerator negative 10 minus 16 over denominator 13 end fraction end cell row blank equals cell fraction numerator negative 26 over denominator 13 end fraction end cell row blank equals cell negative 2 end cell end table$

Jadi, $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow a of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 5 f open parentheses x close parentheses minus open parentheses g open parentheses x close parentheses close parentheses squared over denominator h open parentheses x close parentheses end fraction end cell end table equals negative 2$ .

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