Pertanyaan

Jika 2 m = 3 n = 6 P Nilai dari p = … + 3 m u .

Jika $2^{m} = 3^{n} = 6^{P}$ Nilai dari $p = \dots + 3 m u .$

$fraction numerator straight m minus straight n over denominator mn end fraction$
$fraction numerator mn over denominator straight m plus straight n end fraction$
$fraction numerator straight m plus straight n over denominator mn end fraction$
$fraction numerator mn over denominator straight m minus 2 end fraction$
$fraction numerator straight n over denominator straight m minus straight n end fraction$

D. Citra

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Ingat kembali: Dengan demikian: Karena maka Dengan demikian, nilai adalah Jadi, jawaban yang tepat adalah B.

Ingat kembali:

log presuperscript a space b to the power of c equals c times log presuperscript a space b

$log presuperscript straight a space straight b equals fraction numerator straight c times log space straight b over denominator straight c times log space straight a end fraction$

straight a equals straight b rightwards arrow log presuperscript straight x space straight a equals log presuperscript straight x space straight b

log presuperscript straight a space straight b times straight c equals log presuperscript straight a space straight b plus log presuperscript straight a space straight c

Dengan demikian:

$table attributes columnalign right center left columnspacing 0px end attributes row cell 2 to the power of m end cell equals cell 3 to the power of n end cell row cell log space 2 to the power of m end cell equals cell log space 3 to the power of n end cell row cell m times log space 2 end cell equals cell n times log space 3 end cell row cell m over n end cell equals cell fraction numerator log space 3 over denominator log space 2 end fraction end cell end table$

Karena 3 to the power of n equals 6 to the power of p maka

$table attributes columnalign right center left columnspacing 0px end attributes row cell 3 to the power of n end cell equals cell 6 to the power of p end cell row cell log space 3 to the power of n end cell equals cell log space 6 to the power of p end cell row cell n space log space 3 end cell equals cell p space log space 6 end cell row cell n space scriptbase log space end scriptbase presuperscript 2 3 end cell equals cell p space scriptbase log space end scriptbase presuperscript 2 6 end cell row cell up diagonal strike n times fraction numerator m over denominator up diagonal strike n end fraction end cell equals cell p space scriptbase log space end scriptbase presuperscript 2 6 end cell row m equals cell p times scriptbase log space end scriptbase presuperscript 2 2 times 3 end cell row m equals cell p open parentheses scriptbase log space end scriptbase presuperscript 2 2 plus scriptbase log space end scriptbase presuperscript 2 3 close parentheses end cell row m equals cell p open parentheses 1 plus m over n close parentheses end cell row p equals cell fraction numerator m over denominator 1 plus m over n end fraction end cell row p equals cell fraction numerator m n over denominator m plus n end fraction end cell end table$

Dengan demikian, nilai adalah $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator m n over denominator m plus n end fraction end cell end table$

Jadi, jawaban yang tepat adalah B.