Jika maka

Pertanyaan

Jika $begin mathsize 14px style f open parentheses x close parentheses equals 2 x minus 6 end style$ maka $begin mathsize 14px style f to the power of negative 1 end exponent left parenthesis x right parenthesis equals space... end style$

... $space$
... $undefined$

Pembahasan Video:

Pembahasan Soal:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals y row cell 2 x minus 6 end cell equals y row cell 2 x end cell equals cell y plus 6 end cell row x equals cell fraction numerator y plus 6 over denominator 2 end fraction end cell end table end style$

Karena $begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank f end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses x close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table end style$ , maka $begin mathsize 14px style f to the power of negative 1 end exponent table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses y close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table end style$ .

Akibatnya, didapat invers fungsinya adalah sebagai berikut.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals x row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals cell fraction numerator y plus 6 over denominator 2 end fraction end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x plus 6 over denominator 2 end fraction end cell end table end style$

Jadi, $begin mathsize 14px style f to the power of negative 1 end exponent open parentheses x close parentheses end style$ adalah $begin mathsize 14px style fraction numerator x plus 6 over denominator 2 end fraction. end style$

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 05 Mei 2021

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