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Pertanyaan

Jika x = 7 199 ( 2 198 × 1 5 199 + 6 199 × 5 197 ) 2 × 5 197 ( 2 197 × 2 1 200 − 7 200 × 6 198 ) ​ , maka nilai dari x 4 1 ​ adalah ....

Jika , maka nilai dari adalah ....

  1. begin mathsize 14px style 7 over 9 end style

  2. size 14px 49 over size 14px 7

  3. fraction numerator square root of size 14px 7 over denominator size 14px 3 end fraction

  4. fraction numerator size 14px 7 square root of size 14px 3 over denominator size 14px 3 end fraction

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

Pembahasan

Ingat bahwa , , dan . Maka, bentuk pada soal dapat kita sederhanakan menjadi Dengan demikian, kita peroleh Jadi, jawaban yang tepat adalah C.

Ingat bahwa begin mathsize 14px style n-th root of a to the power of m end root equals a to the power of m over n end exponent end style, begin mathsize 14px style open parentheses a over b close parentheses to the power of n equals a to the power of n over b to the power of n end style, dan begin mathsize 14px style open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent end style.

Maka, bentuk pada soal dapat kita sederhanakan menjadi

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row x equals cell fraction numerator 2 cross times 5 to the power of 197 left parenthesis 2 to the power of 197 cross times 21 to the power of 200 minus 7 to the power of 200 cross times 6 to the power of 198 right parenthesis over denominator 7 to the power of 199 left parenthesis 2 to the power of 198 cross times 15 to the power of 199 plus 6 to the power of 199 cross times 5 to the power of 197 right parenthesis end fraction end cell row blank equals cell fraction numerator 2 cross times 5 to the power of 197 left parenthesis 2 to the power of 197 cross times 3 to the power of 200 cross times 7 to the power of 200 minus 7 to the power of 200 cross times 2 to the power of 198 cross times 3 to the power of 198 right parenthesis over denominator 7 to the power of 199 left parenthesis 2 to the power of 198 cross times 3 to the power of 199 cross times 5 to the power of 199 plus 2 to the power of 199 cross times 3 to the power of 199 cross times 5 to the power of 197 right parenthesis end fraction end cell row blank equals cell fraction numerator 2 cross times 5 to the power of 197 cross times 7 to the power of 199 left parenthesis 2 to the power of 197 cross times 3 to the power of 200 cross times 7 minus 7 cross times 2 to the power of 198 cross times 3 to the power of 198 right parenthesis over denominator 2 cross times 5 to the power of 197 cross times 7 to the power of 199 left parenthesis 2 to the power of 197 cross times 3 to the power of 199 cross times 5 squared plus 2 to the power of 198 cross times 3 to the power of 199 right parenthesis end fraction end cell row blank equals cell fraction numerator 2 to the power of 197 cross times 3 to the power of 200 cross times 7 minus 7 cross times 2 to the power of 198 cross times 3 to the power of 198 over denominator 2 to the power of 197 cross times 3 to the power of 199 cross times 5 squared plus 2 to the power of 198 cross times 3 to the power of 199 end fraction end cell row blank equals cell fraction numerator 2 to the power of 197 cross times 3 to the power of 198 left parenthesis 3 squared cross times 7 minus 7 cross times 2 right parenthesis over denominator 2 to the power of 197 cross times 3 to the power of 198 left parenthesis 3 cross times 5 squared plus 2 cross times 3 right parenthesis end fraction end cell row blank equals cell fraction numerator 3 squared cross times 7 minus 7 cross times 2 over denominator 3 cross times 5 squared plus 2 cross times 3 end fraction end cell row blank equals cell fraction numerator 9 cross times 7 minus 7 cross times 2 over denominator 3 cross times 25 plus 2 cross times 3 end fraction end cell row blank equals cell fraction numerator 63 minus 14 over denominator 75 plus 6 end fraction end cell row blank equals cell 49 over 81 end cell end table end style

Dengan demikian, kita peroleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell x to the power of 1 fourth end exponent end cell equals cell open parentheses 49 over 81 close parentheses to the power of 1 fourth end exponent end cell row blank equals cell open parentheses 7 squared over 3 to the power of 4 close parentheses to the power of 1 fourth end exponent end cell row blank equals cell 7 to the power of begin display style 2 over 4 end style end exponent over 3 to the power of begin display style 4 over 4 end style end exponent end cell row blank equals cell 7 to the power of begin display style 1 half end style end exponent over 3 end cell row blank equals cell fraction numerator square root of 7 over denominator 3 end fraction end cell end table end style

Jadi, jawaban yang tepat adalah C.

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Jika a = 49 , b = 25 , dan c = 243 , maka nilai dari a − 2 3 ​ b 2 7 ​ c − 5 2 ​ a − 1 b 4 c 5 1 ​ ​ adalah ....

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