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Jika bentuk 3 a b 3 c ​ ​ ​ dapat disederhanakan menjadi a x b y c z , maka x − 2 − y − 2 + z − 1 = ...

Jika bentuk  dapat disederhanakan menjadi  , maka  = ...

  1. begin mathsize 14px style 9 end style 

  2. begin mathsize 14px style negative 9 end style  space 

  3. begin mathsize 14px style 18 end style 

  4. begin mathsize 14px style negative 18 end style  space 

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

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Pembahasan

Kita akan menggunakan sifat-sifat berikut ini untuk menjawab pertanyaan di atas. Sehingga kita dapatkan Maka dari bentuk , kita dapatkan Sehingga Jadi, jawaban yang tepat adalah B.

Kita akan menggunakan sifat-sifat berikut ini untuk menjawab pertanyaan di atas.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n-th root of a to the power of m end root end cell equals cell a to the power of m over n end exponent blank end cell row cell left parenthesis a blank x blank b right parenthesis to the power of n end cell equals cell a to the power of n cross times b to the power of n end cell row cell left parenthesis a over b right parenthesis to the power of n end cell equals cell a to the power of n over b to the power of n end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m blank x blank n end exponent end cell end table end style 

Sehingga kita dapatkan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell cube root of a square root of b cube root of c end root end root end cell equals cell open parentheses a square root of b cube root of c end root close parentheses to the power of 1 third end exponent end cell row blank equals cell open parentheses a open parentheses b cube root of c close parentheses to the power of 1 half end exponent close parentheses to the power of 1 third end exponent end cell row blank equals cell open parentheses a open parentheses b c to the power of 1 third end exponent close parentheses to the power of 1 half end exponent close parentheses to the power of 1 third end exponent end cell row blank equals cell open parentheses a b to the power of 1 half end exponent c to the power of 1 third cross times 1 half end exponent close parentheses to the power of 1 third end exponent end cell row blank equals cell a to the power of 1 third end exponent b to the power of 1 half cross times 1 third end exponent c to the power of 1 third cross times 1 half cross times 1 third end exponent end cell row blank equals cell a to the power of 1 third end exponent b to the power of 1 over 6 end exponent c to the power of 1 over 18 end exponent end cell end table end style     

Maka dari bentuk size 14px a to the power of size 14px x size 14px b to the power of size 14px y size 14px c to the power of size 14px z size 14px equals size 14px a to the power of size 14px 1 over size 14px 3 end exponent size 14px b to the power of size 14px 1 over size 14px 6 end exponent size 14px c to the power of size 14px 1 over size 14px 18 end exponent, kita dapatkan

size 14px x size 14px equals size 14px 1 over size 14px 3 blank size 14px comma blank size 14px y size 14px equals size 14px 1 over size 14px 6 blank size 14px comma blank size 14px z size 14px equals size 14px 1 over size 14px 18   

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell x to the power of negative 2 end exponent minus y to the power of negative 2 end exponent plus z to the power of negative 1 end exponent end cell equals cell 1 over x squared minus 1 over y squared plus 1 over z end cell row blank equals cell 1 over blank minus 1 over blank plus fraction numerator 1 over denominator 1 over 18 end fraction end cell row blank equals cell fraction numerator 1 over denominator 1 over 9 end fraction minus fraction numerator 1 over denominator 1 over 36 end fraction plus fraction numerator 1 over denominator 1 over 18 end fraction end cell row blank equals cell 9 minus 36 plus 18 end cell row blank equals cell negative 9 end cell end table end style    

Jadi, jawaban yang tepat adalah B.

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