Pertanyaan

Jika ,maka ....

Jika , maka ....

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Jawaban terverifikasi

Jawaban

jawabannya adalah A.

Pembahasan

Perhatikan perhitungan berikut ini! Jadi, jawabannya adalah A.

Perhatikan perhitungan berikut ini!

$begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell log presubscript blank presuperscript 4 invisible function application open parentheses fraction numerator 2 over denominator square root of straight a plus square root of straight b end fraction plus fraction numerator 2 over denominator square root of straight a minus square root of straight b end fraction close parentheses end cell equals cell log presubscript blank presuperscript 4 invisible function application open parentheses fraction numerator 2 open parentheses square root of straight a minus square root of straight b close parentheses plus 2 open parentheses square root of straight a plus square root of straight b close parentheses over denominator open parentheses square root of straight a plus square root of straight b close parentheses open parentheses square root of straight a minus square root of straight b close parentheses end fraction close parentheses end cell row blank equals cell log presubscript blank presuperscript 4 invisible function application open parentheses fraction numerator 2 square root of straight a minus 2 square root of straight b plus 2 square root of straight a plus 2 square root of straight b over denominator straight a minus straight b end fraction close parentheses end cell row blank equals cell log presubscript blank presuperscript 4 invisible function application open parentheses fraction numerator 4 square root of straight a over denominator straight a minus straight b end fraction close parentheses end cell row blank equals cell log presubscript blank presuperscript 4 invisible function application 4 square root of straight a minus log presubscript blank presuperscript 4 invisible function application left parenthesis straight a minus straight b right parenthesis end cell row blank equals cell log presubscript blank presuperscript 4 invisible function application 4 plus log presubscript blank presuperscript 4 invisible function application square root of straight a minus log presubscript blank presuperscript 4 invisible function application left parenthesis straight a minus straight b right parenthesis end cell row blank equals cell 1 plus log presubscript blank presuperscript 2 squared end presuperscript invisible function application straight a to the power of 1 half end exponent minus log presubscript blank presuperscript 2 squared end presuperscript invisible function application left parenthesis straight a minus straight b right parenthesis end cell row blank equals cell 1 plus fraction numerator 1 half over denominator 2 end fraction log presubscript blank presuperscript 2 invisible function application straight a minus 1 half log presubscript blank presuperscript 2 invisible function application left parenthesis straight a minus straight b right parenthesis end cell row blank equals cell 1 plus 1 fourth log presubscript blank presuperscript 2 invisible function application straight a minus 1 half left parenthesis 4 right parenthesis end cell row blank equals cell 1 plus 1 fourth log presubscript blank presuperscript 2 invisible function application straight a minus 2 end cell row blank equals cell 1 fourth log presubscript blank presuperscript 2 invisible function application straight a minus 1 end cell row blank equals cell fraction numerator log presubscript blank presuperscript 2 invisible function application straight a minus 4 over denominator 4 end fraction end cell end table end style$

Jadi, jawabannya adalah A.

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