Pertanyaan

Jika diketahui g ( x ) = 2 x − 5 x + 4 , maka ( f ∘ g ) ( x ) = 2 x − 5 x + 17 maka f ( − 3 ) =...

Jika diketahui $g (x) = \frac{x + 4}{2 x - 5}, maka (f \circ g) (x) = \frac{x + 17}{2 x - 5} maka f (- 3)$ =...

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-5

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

Penyelesaian:

$g left parenthesis x right parenthesis equals fraction numerator x plus 4 over denominator 2 x minus 5 end fraction g to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator 5 x plus 4 over denominator 2 x minus 1 end fraction left parenthesis f ring operator g right parenthesis left parenthesis x right parenthesis equals fraction numerator x plus 17 over denominator 2 x minus 5 end fraction f open parentheses fraction numerator x plus 4 over denominator 2 x minus 5 end fraction close parentheses equals fraction numerator x plus 17 over denominator 2 x minus 5 end fraction f left parenthesis x right parenthesis equals fraction numerator begin display style fraction numerator 5 x plus 4 over denominator 2 x minus 1 end fraction end style plus 17 over denominator 2 open parentheses begin display style fraction numerator 5 x plus 4 over denominator 2 x minus 1 end fraction end style close parentheses equals 5 end fraction f left parenthesis x right parenthesis equals fraction numerator begin display style fraction numerator 5 x plus 4 plus 17 left parenthesis 2 x minus 1 right parenthesis over denominator 2 x minus 1 end fraction end style over denominator begin display style fraction numerator 10 x plus 8 minus 5 left parenthesis 2 x minus 1 right parenthesis over denominator 2 x minus 1 end fraction end style end fraction f left parenthesis x right parenthesis equals fraction numerator 5 x plus 34 x plus 4 minus 17 over denominator 2 x minus 1 end fraction. fraction numerator 2 x minus 1 over denominator 10 x minus 10 x plus 8 plus 5 end fraction equals fraction numerator 39 x minus 13 over denominator 13 end fraction f left parenthesis x right parenthesis equals 2 x minus 1 f left parenthesis negative 3 right parenthesis equals 2 left parenthesis negative 3 right parenthesis minus 1 equals negative 6 minus 1 equals negative 7$