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Pertanyaan

Jika dan tan⁡ θ < 1, maka tan⁡ θ = ....

Jika begin mathsize 14px style tan invisible function application open parentheses straight pi over 4 plus straight theta close parentheses equals 4 tan invisible function application open parentheses straight pi over 4 minus straight theta close parentheses end style dan tan⁡ θ < 1, maka tan⁡ θ = ....

  1. begin mathsize 14px style 1 third end style 

  2. begin mathsize 14px style 1 third square root of 3 end style 

  3. begin mathsize 14px style 0 end style 

  4. begin mathsize 14px style negative 1 third square root of 3 end style 

  5. begin mathsize 14px style negative 1 third end style 

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R. Rohmat

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

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Pembahasan

Perhatikan bahwa Karena tan⁡ θ &lt; 1, maka . Jadi, jawaban yang tepat adalah A.

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell tan invisible function application open parentheses straight pi over 4 plus straight theta close parentheses end cell equals cell 4 tan invisible function application open parentheses straight pi over 4 minus straight theta close parentheses end cell row cell fraction numerator tan invisible function application straight pi over 4 plus tan invisible function application straight theta over denominator 1 minus tan invisible function application straight pi over 4 tan invisible function application straight theta end fraction end cell equals cell 4 times fraction numerator tan invisible function application straight pi over 4 minus tan invisible function application straight theta over denominator 1 plus tan invisible function application straight pi over 4 tan invisible function application straight theta end fraction end cell row cell fraction numerator 1 plus tan invisible function application straight theta over denominator 1 minus 1 times tan invisible function application straight theta end fraction end cell equals cell 4 times fraction numerator 1 minus tan invisible function application straight theta over denominator 1 plus 1 times tan invisible function application straight theta end fraction end cell row cell fraction numerator 1 plus tan invisible function application straight theta over denominator 1 minus tan invisible function application straight theta end fraction end cell equals cell 4 times fraction numerator 1 minus tan invisible function application straight theta over denominator 1 plus tan invisible function application straight theta end fraction end cell row cell open parentheses 1 plus tan invisible function application straight theta close parentheses open parentheses 1 plus tan invisible function application straight theta close parentheses end cell equals cell 4 open parentheses 1 minus tan invisible function application straight theta close parentheses open parentheses 1 minus tan invisible function application straight theta close parentheses end cell row cell 1 plus 2 tan invisible function application straight theta plus tan squared invisible function application straight theta end cell equals cell 4 open parentheses 1 minus 2 tan invisible function application straight theta plus tan squared invisible function application straight theta close parentheses end cell row cell 1 plus 2 tan invisible function application straight theta plus tan squared invisible function application straight theta end cell equals cell 4 minus 8 tan invisible function application straight theta plus 4 tan squared invisible function application straight theta end cell row 0 equals cell 3 tan squared invisible function application straight theta minus 10 tan invisible function application straight theta plus 3 end cell row 0 equals cell open parentheses 3 tan invisible function application straight theta minus 1 close parentheses open parentheses tan invisible function application straight theta minus 3 close parentheses end cell row cell tan invisible function application straight theta end cell equals cell 1 third text atau end text tan invisible function application straight theta equals 3 end cell end table end style 


Karena tan⁡ θ < 1, maka begin mathsize 14px style tan invisible function application straight theta equals 1 third end style. 

Jadi, jawaban yang tepat adalah A.

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