Iklan

Pertanyaan

Jika 3 tan θ = x + 1 dan 0 < θ < 2 π ​ , nyatakan ekspresi 2 θ + 1 − tan 2 θ 2 tan θ ​ dalam fungsi dari x

Jika  dan , nyatakan ekspresi  dalam fungsi dari  

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

08

:

45

:

00

Klaim

Iklan

W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

.

 table attributes columnalign right center left columnspacing 0px end attributes row cell 2 theta plus fraction numerator 2 space tan space theta over denominator 1 minus tan squared space theta end fraction end cell equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator 6 x plus 6 over denominator 8 minus x squared minus 2 x end fraction end cell end table.

Pembahasan

Jika dan , maka: Interval berada pada kuadran I, berarti seluruh nilai perbandingan trigonometri bernilai positif. Sehingga ekspresi dalam fungsi dari dapat ditentukan dengan cara: Jadi, .

Jika 3 space tan space theta equals x plus 1 dan 0 less than theta less than straight pi over 2, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 space tan space theta end cell equals cell x plus 1 end cell row cell tan space theta end cell equals cell fraction numerator x plus 1 over denominator 3 end fraction end cell row theta equals cell tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses end cell end table    

Interval 0 less than theta less than straight pi over 2 berada pada kuadran I, berarti seluruh nilai perbandingan trigonometri bernilai positif. Sehingga ekspresi 2 theta plus fraction numerator 2 space tan space theta over denominator 1 minus tan squared space theta end fraction dalam fungsi dari x dapat ditentukan dengan cara:

 begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 theta plus fraction numerator 2 space tan space theta over denominator 1 minus tan squared space theta end fraction end cell equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator 2 space open parentheses begin display style fraction numerator x plus 1 over denominator 3 end fraction end style close parentheses over denominator 1 minus open parentheses begin display style fraction numerator x plus 1 over denominator 3 end fraction end style close parentheses squared end fraction end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator begin display style fraction numerator 2 open parentheses x plus 1 close parentheses over denominator 3 end fraction end style over denominator 1 minus begin display style fraction numerator x squared plus 2 x plus 1 over denominator 9 end fraction end style end fraction end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator begin display style fraction numerator 2 x plus 2 over denominator 3 end fraction end style over denominator begin display style fraction numerator 9 minus open parentheses x squared plus 2 x plus 1 close parentheses over denominator 9 end fraction end style end fraction end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus open parentheses fraction numerator 2 x plus 2 over denominator 3 end fraction close parentheses times open parentheses fraction numerator 9 over denominator 9 minus open parentheses x squared plus 2 x plus 1 close parentheses end fraction close parentheses end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus open parentheses fraction numerator 2 x plus 2 over denominator 3 end fraction close parentheses times open parentheses fraction numerator 9 over denominator 9 minus x squared minus 2 x minus 1 end fraction close parentheses end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus open parentheses fraction numerator 2 x plus 2 over denominator up diagonal strike 3 end fraction close parentheses times open parentheses fraction numerator up diagonal strike 9 space 3 over denominator 8 minus x squared minus 2 x end fraction close parentheses end cell row blank equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator 6 x plus 6 over denominator 8 minus x squared minus 2 x end fraction end cell end table end style 

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row cell 2 theta plus fraction numerator 2 space tan space theta over denominator 1 minus tan squared space theta end fraction end cell equals cell 2 open square brackets tan to the power of negative 1 end exponent space open parentheses fraction numerator x plus 1 over denominator 3 end fraction close parentheses close square brackets plus fraction numerator 6 x plus 6 over denominator 8 minus x squared minus 2 x end fraction end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

22

Iklan

Pertanyaan serupa

Hitung ekspresi berikut tanpa menggunakan kalkulator maupun tabel trigonometri. a. cotan [ cos − 1 ( − 2 1 ​ ) + cos − 1 ( 0 ) + tan − 1 ( 3 ​ 1 ​ ) ]

1

3.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia