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Pertanyaan

Jika g ( x − 2 ) = x + 2 x − 4 ​ dan f ( x ) = x 2 + 3 dengan x  = 2 , maka ( f ∘ g − 1 ) ( 2 ) = ...

Jika  dan  dengan , maka   

  1. begin mathsize 14px style 103 end style

  2. begin mathsize 14px style 104 end style

  3. begin mathsize 14px style 130 end style

  4. begin mathsize 14px style 134 end style

  5. begin mathsize 14px style 143 end style

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

Pembahasan

Perhatikan bahwa : Sehingga dibutuhkan nilai dari terlebih dahulu. Perhatikan bahwa : Supaya didapat , maka : Sehingga jika disubstitusikan x = -8 , didapat : Sehingga : Karena , maka : Jadi, jawaban yang tepat adalah A.

Perhatikan bahwa :

begin mathsize 14px style left parenthesis straight f ring operator straight g to the power of negative 1 end exponent right parenthesis left parenthesis 2 right parenthesis equals straight f left parenthesis straight g to the power of negative 1 end exponent left parenthesis 2 right parenthesis right parenthesis end style

Sehingga dibutuhkan nilai dari begin mathsize 14px style straight g to the power of negative 1 end exponent left parenthesis 2 right parenthesis end style terlebih dahulu.

Perhatikan bahwa :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g left parenthesis straight x minus 2 right parenthesis end cell equals cell fraction numerator straight x minus 4 over denominator straight x plus 2 end fraction end cell row cell straight g to the power of negative 1 end exponent open parentheses fraction numerator straight x minus 4 over denominator straight x plus 2 end fraction close parentheses end cell equals cell straight x minus 2 end cell end table end style 

Supaya didapat undefined , maka :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator straight x minus 4 over denominator straight x plus 2 end fraction end cell equals cell 2 space end cell row cell straight x minus 4 end cell equals cell 2 left parenthesis straight x plus 2 right parenthesis space end cell row cell straight x minus 4 end cell equals cell 2 straight x plus 4 space end cell row cell straight x minus 2 straight x end cell equals cell 4 plus 4 space end cell row cell negative straight x end cell equals cell 8 space end cell row straight x equals cell negative 8 end cell end table end style 

Sehingga jika disubstitusikan = -8 , didapat :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g to the power of negative 1 end exponent open parentheses fraction numerator straight x minus 4 over denominator straight x plus 2 end fraction close parentheses end cell equals cell straight x minus 2 end cell row cell straight g to the power of negative 1 end exponent open parentheses fraction numerator negative 8 minus 4 over denominator negative 8 plus 2 end fraction close parentheses end cell equals cell negative 8 minus 2 end cell row cell straight g to the power of negative 1 end exponent open parentheses fraction numerator negative 12 over denominator negative 6 end fraction close parentheses end cell equals cell negative 10 end cell row cell straight g to the power of negative 1 end exponent left parenthesis 2 right parenthesis end cell equals cell negative 10 end cell end table end style 

Sehingga :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis straight f ring operator straight g to the power of negative 1 end exponent right parenthesis left parenthesis 2 right parenthesis end cell equals cell straight f open parentheses straight g to the power of negative 1 end exponent left parenthesis 2 right parenthesis close parentheses end cell row blank equals cell straight f left parenthesis negative 10 right parenthesis end cell end table end style

Karena undefined , maka :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis straight f ring operator straight g to the power of negative 1 end exponent right parenthesis left parenthesis 2 right parenthesis end cell equals cell straight f left parenthesis negative 10 right parenthesis end cell row blank equals cell left parenthesis negative 10 right parenthesis squared plus 3 end cell row blank equals cell 100 plus 3 end cell row blank equals 103 end table end style 

Jadi, jawaban yang tepat adalah A.

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