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Pertanyaan

J1ka a  = 0, maka ( 16 a 4 ) 3 1 ​ ( − 2 a ) 3 . ( 2 a ) − 3 2 ​ ​ = ...

J1ka a  0, maka

  1. negative 2 a squared

  2. 2 a squared

  3. -2a

  4. 2 squared a

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

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Pembahasan

fraction numerator left parenthesis negative 2 a right parenthesis cubed. left parenthesis 2 a right parenthesis to the power of negative begin display style 2 over 3 end style end exponent over denominator left parenthesis 16 a to the power of 4 right parenthesis to the power of begin display style 1 third end style end exponent end fraction  equals fraction numerator open parentheses left parenthesis negative 2 right parenthesis to the power of 3. end exponent a cubed close parentheses begin display style. end style begin display style open parentheses 2 to the power of negative 2 over 3 end exponent. a to the power of negative 2 over 3 end exponent close parentheses end style over denominator open parentheses 16 to the power of begin display style 1 third end style end exponent. left parenthesis a to the power of 4 right parenthesis to the power of begin display style 1 third end style end exponent end exponent close parentheses end fraction  equals fraction numerator negative 2 to the power of 3 plus open parentheses negative begin display style 2 over 3 end style close parentheses end exponent.2 to the power of 3 plus open parentheses negative 2 over 3 close parentheses end exponent over denominator 2 to the power of begin display style 4 over 3 end style end exponent. a to the power of begin display style 4 over 3 end style end exponent end fraction  equals negative fraction numerator 2 to the power of begin display style 7 over 3 end style end exponent. a to the power of begin display style 7 over 3 end style end exponent over denominator 2 to the power of begin display style 4 over 3 end style end exponent. a to the power of begin display style 4 over 3 end style end exponent end fraction equals negative 2 to the power of 7 over 3 minus 4 over 3 end exponent. a to the power of 7 over 3 minus 4 over 3 end exponent  equals negative 2 to the power of 1. a to the power of 1 equals negative 2 a

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Konsep Kilat

Pengertian Bilangan Berpangkat

Sifat Bilangan Berpangkat

Persamaan Bilangan Berpangkat

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Alya Putri fariza

Pembahasan tidak lengkap

James Harden

Pembahasan tidak menjawab soal Jawaban tidak sesuai Pembahasan tidak lengkap

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Bentuk sederhana dari ( a − 2 b 4 c 2 ) − 2 ( 2 a − 1 b − 3 c − 2 ) − 3 ​ adalah ....

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