J1ka a = 0, maka (16a4)31(−2a)3.(2a)−32=...

Pertanyaan

J1ka a $\neq$ 0, maka $fraction numerator left parenthesis negative 2 a right parenthesis cubed. left parenthesis 2 a right parenthesis to the power of negative begin display style 2 over 3 end style end exponent over denominator left parenthesis 16 a to the power of 4 right parenthesis to the power of begin display style 1 third end style end exponent end exponent end fraction equals...$

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Pembahasan

$fraction numerator left parenthesis negative 2 a right parenthesis cubed. left parenthesis 2 a right parenthesis to the power of negative begin display style 2 over 3 end style end exponent over denominator left parenthesis 16 a to the power of 4 right parenthesis to the power of begin display style 1 third end style end exponent end fraction equals fraction numerator open parentheses left parenthesis negative 2 right parenthesis to the power of 3. end exponent a cubed close parentheses begin display style. end style begin display style open parentheses 2 to the power of negative 2 over 3 end exponent. a to the power of negative 2 over 3 end exponent close parentheses end style over denominator open parentheses 16 to the power of begin display style 1 third end style end exponent. left parenthesis a to the power of 4 right parenthesis to the power of begin display style 1 third end style end exponent end exponent close parentheses end fraction equals fraction numerator negative 2 to the power of 3 plus open parentheses negative begin display style 2 over 3 end style close parentheses end exponent.2 to the power of 3 plus open parentheses negative 2 over 3 close parentheses end exponent over denominator 2 to the power of begin display style 4 over 3 end style end exponent. a to the power of begin display style 4 over 3 end style end exponent end fraction equals negative fraction numerator 2 to the power of begin display style 7 over 3 end style end exponent. a to the power of begin display style 7 over 3 end style end exponent over denominator 2 to the power of begin display style 4 over 3 end style end exponent. a to the power of begin display style 4 over 3 end style end exponent end fraction equals negative 2 to the power of 7 over 3 minus 4 over 3 end exponent. a to the power of 7 over 3 minus 4 over 3 end exponent equals negative 2 to the power of 1. a to the power of 1 equals negative 2 a$

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