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Hitunglah nilai x yang memenuhi persamaan 5 2 x − 3 2 x = 5 2 x − 1 + 3 2 x − 1 .

Hitunglah nilai  yang memenuhi persamaan .

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N. Puspita

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nilai yang memenuhi persamaan tersebut adalah .

nilai x yang memenuhi persamaan tersebut adalah 1 half.

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Ingat kembali bentuk persamaan eksponen berikut: Persamaan , dapat diubah menjadi: Sehingga: Jadi, nilai yang memenuhi persamaan tersebut adalah .

Ingat kembali bentuk persamaan eksponen berikut:

begin mathsize 12px style a to the power of f open parentheses x close parentheses end exponent equals b to the power of f open parentheses x close parentheses end exponent comma space a greater than 0 comma space a not equal to 1 comma space b greater than 0 comma space b not equal to 1 comma space dan space a not equal to b rightwards arrow f open parentheses x close parentheses equals 0 end style  

Persamaan 5 to the power of 2 x end exponent minus 3 to the power of 2 x end exponent equals 5 to the power of 2 x minus 1 end exponent plus 3 to the power of 2 x minus 1 end exponent, dapat diubah menjadi:

table attributes columnalign right center left columnspacing 0px end attributes row cell 5 to the power of 2 x end exponent minus 3 to the power of 2 x end exponent end cell equals cell 5 to the power of 2 x minus 1 end exponent plus 3 to the power of 2 x minus 1 end exponent end cell row cell 5 to the power of 2 x end exponent minus 3 to the power of 2 x end exponent end cell equals cell 5 to the power of 2 x end exponent times 5 to the power of negative 1 end exponent plus 3 to the power of 2 x end exponent times 3 to the power of negative 1 end exponent end cell row cell 5 to the power of 2 x end exponent minus 3 to the power of 2 x end exponent end cell equals cell 5 to the power of 2 x end exponent times 1 fifth plus 3 to the power of 2 x end exponent times 1 third end cell row cell 5 to the power of 2 x end exponent minus 3 to the power of 2 x end exponent end cell equals cell 5 to the power of 2 x end exponent over 5 plus 3 to the power of 2 x end exponent over 3 end cell row cell 5 to the power of 2 x end exponent minus 5 to the power of 2 x end exponent over 5 end cell equals cell 3 to the power of 2 x end exponent over 3 plus 3 to the power of 2 x end exponent end cell row cell 5 to the power of 2 x end exponent open parentheses 1 minus 1 fifth close parentheses end cell equals cell 3 to the power of 2 x end exponent open parentheses 1 third plus 1 close parentheses end cell row cell 5 to the power of 2 x end exponent open parentheses 5 over 5 minus 1 fifth close parentheses end cell equals cell 3 to the power of 2 x end exponent open parentheses 1 third plus 3 over 3 close parentheses end cell row cell 5 to the power of 2 x end exponent open parentheses fraction numerator up diagonal strike 4 over denominator 5 end fraction close parentheses end cell equals cell 3 to the power of 2 x end exponent open parentheses fraction numerator up diagonal strike 4 over denominator 3 end fraction close parentheses end cell row cell 5 to the power of 2 x end exponent open parentheses 1 fifth close parentheses end cell equals cell 3 to the power of 2 x end exponent open parentheses 1 third close parentheses end cell row cell 5 to the power of 2 x end exponent open parentheses 5 to the power of negative 1 end exponent close parentheses end cell equals cell 3 to the power of 2 x end exponent open parentheses 3 to the power of negative 1 end exponent close parentheses end cell row cell 5 to the power of 2 x minus 1 end exponent end cell equals cell 3 to the power of 2 x minus 1 end exponent end cell end table 

Sehingga:

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 x minus 1 end cell equals 0 row cell 2 x end cell equals 1 row x equals cell 1 half end cell end table 

Jadi, nilai x yang memenuhi persamaan tersebut adalah 1 half.

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