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Himpunan penyelesaian dari persamaan kuadrat-kuadr...

Himpunan penyelesaian dari persamaan kuadrat-kuadrat begin mathsize 14px style y equals x squared minus 2 x end style dan begin mathsize 14px style y equals negative x squared plus 6 x end style adalah ....

  1. begin mathsize 14px style open curly brackets open parentheses 0 comma 0 close parentheses semicolon open parentheses 4 comma 8 close parentheses close curly brackets end style

  2. begin mathsize 14px style left curly bracket open parentheses 0 comma 4 close parentheses semicolon open parentheses 0 comma 8 close parentheses right curly bracket end style

  3. begin mathsize 14px style left curly bracket open parentheses 4 comma 0 close parentheses semicolon open parentheses 0 comma 8 close parentheses right curly bracket end style

  4. begin mathsize 14px style left curly bracket open parentheses 4 comma 0 close parentheses semicolon open parentheses 8 comma 0 close parentheses right curly bracket end style

  5. begin mathsize 14px style left curly bracket open parentheses 8 comma 4 close parentheses semicolon open parentheses 0 comma 0 close parentheses right curly bracket end style

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell y subscript 1 end cell equals cell y subscript 2 end cell row cell x squared minus 2 x end cell equals cell negative x squared plus 6 x end cell row cell 2 x squared minus 8 x end cell equals 0 row cell 2 x left parenthesis x minus 4 right parenthesis end cell equals 0 row x equals cell 0 space atau space x equals 4 end cell row blank blank blank row cell Untuk space x end cell equals cell 0 space maka end cell row cell y subscript 1 end cell equals cell negative x squared plus 6 x end cell row cell y subscript 1 end cell equals cell 0 squared plus 6 left parenthesis 0 right parenthesis end cell row cell y subscript 1 end cell equals 0 row blank blank cell Titik space left parenthesis 0 comma 0 right parenthesis end cell row blank blank blank row cell Untuk space x end cell equals cell 4 space maka end cell row cell y subscript 1 end cell equals cell negative x squared plus 6 x end cell row cell y subscript 1 end cell equals cell negative open parentheses 4 close parentheses squared plus 6 left parenthesis 4 right parenthesis end cell row cell y subscript 1 end cell equals cell negative 16 plus 24 end cell row cell y subscript 1 end cell equals 8 row blank blank cell Titik space left parenthesis 4 comma 8 right parenthesis end cell row blank blank blank row blank blank blank end table end style  

 

Jadi jawaban yang tepat adalah A

 

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