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Himpunan penyelesaian dari persamaan 2 cos 3x o = 1, untuk 0 o ≤ x ≤ 180 o adalah ....

Himpunan penyelesaian dari persamaan 2 cos 3xo = 1, untuk 0o ≤ x ≤ 180o adalah ....

  1. {0o, 20o, 60o}

  2. {0o, 20o, 100o}

  3. {20o, 60o, 100o}

  4. {20o, 100o, 140o}

  5. {100o, 140o, 180o}

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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Pembahasan

Sehingga, nilai x yang memenuhipersamaan untuk adalah:

size 12px cos size 12px space size 12px x to the power of size 12px o size 12px space size 12px equals size 12px space size 12px cos size 12px space size 12px alpha size 12px x size 12px space size 12px equals size 12px space size 12px plus-or-minus size 12px space size 12px alpha size 12px space size 12px plus size 12px space size 12px k size 12px. size 12px 360 to the power of size 12px o size 12px space

Sehingga, nilai x yang memenuhi persamaan size 12px 2 size 12px space size 12px cos size 12px space size 12px 3 size 12px x to the power of size 12px o size 12px space size 12px equals size 12px space size 12px 1 untuk size 12px 0 to the power of size 12px o size 12px space size 12px less or equal than size 12px space size 12px x size 12px space size 12px less or equal than size 12px space size 12px 180 to the power of size 12px oadalah:

begin mathsize 12px style cos space 3 x to the power of o equals 1 half space cos space 3 x to the power of o equals cos space 60 to the power of o space 3 x to the power of o equals plus-or-minus space 60 to the power of o plus k.360 to the power of o space x to the power of o equals plus-or-minus space 20 to the power of o plus k.120 to the power of o  x equals 20 to the power of o space plus space k.120 to the power of o space u n t u k space k space equals space 0 space rightwards arrow space x space equals space 20 to the power of o space u n t u k space k space equals space 1 space rightwards arrow space x space equals space 140 to the power of o  x equals – 20 to the power of o space plus space k.120 to the power of o space u n t u k space k space equals space 1 space rightwards arrow space x space equals space 100 to the power of o space  Jadi comma space nilai space straight x space yang space memenuhi space adalah space left curly bracket 20 to the power of o comma space 100 to the power of o comma space 140 to the power of o right curly bracket. end style

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