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Hasil dari ∫ 0 1 ​ 3 x 3 x 2 + 1 ​ d x = ...

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  1. begin mathsize 12px style 7 over 2 end style  

  2. begin mathsize 12px style 8 over 3 end style  

  3. begin mathsize 12px style 7 over 3 end style  

  4. begin mathsize 12px style 4 over 3 end style  

  5. size 12px 2 over size 12px 3  

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Gunakan integral substitusi Misalkan

Gunakan integral substitusi

Misalkan begin mathsize 12px style u equals 3 x squared plus 1 open curly brackets table attributes columnalign left end attributes row cell x equals 0 rightwards double arrow u equals 1 end cell row cell x equals 1 rightwards double arrow u equals 4 end cell end table close end style  

begin mathsize 12px style fraction numerator d u over denominator d x end fraction equals 6 x rightwards double arrow d x equals fraction numerator d u over denominator 6 x end fraction   integral subscript 0 superscript 1 3 x square root of 3 x squared plus 1 end root space d x equals integral subscript 1 superscript 4 3 x square root of u space fraction numerator begin display style d u end style over denominator begin display style 6 x end style end fraction equals 1 half integral subscript 1 superscript 4 u to the power of 1 half end exponent space d u equals 1 half times 2 over 3 u to the power of 3 over 2 end exponent open table attributes columnalign right end attributes row 4 row 1 end table close curly brackets equals 1 third open parentheses 4 to the power of 3 over 2 end exponent minus 1 to the power of fraction numerator begin display style 3 end style over denominator begin display style 2 end style end fraction end exponent close parentheses equals fraction numerator begin display style 1 end style over denominator begin display style 3 end style end fraction open parentheses 8 minus 1 close parentheses equals 7 over 3 end style   

 

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∫ 0 1 ​ x 3 x ​ + 2 3 x ​ d x = ...

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