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Hasil dari ∫ ​ ( 2 x − 1 ) x 2 − x + 5 ​ d x = ....

Hasil dari ....

  1. 1 half left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

  2. 2 over 3 left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

  3. left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

  4. 3 over 2 left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

  5. 2 left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

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A. Acfreelance

Master Teacher

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Pembahasan

M i s a l space u space equals x squared minus x plus 5 comma space m a k a space d u equals left parenthesis 2 x minus 1 right parenthesis d x. space S e h i n g g a comma  integral subscript space superscript space left parenthesis 2 x minus 1 right parenthesis square root of x squared minus x plus 5 end root space d x equals space integral subscript space superscript space square root of u space d u space  equals fraction numerator 1 over denominator 1 half plus 1 end fraction u to the power of 1 half plus 1 end exponent plus C  equals 2 over 3 u square root of u plus C  equals 2 over 3 left parenthesis x squared minus x plus 5 right parenthesis square root of x squared minus x plus 5 end root plus C

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