Roboguru

Hasil  adalah ...

Hasil open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent adalah ...

  1. 1 4 over 9 

  2. 1 2 over 7 

  3. 1 1 over 8 

  4. 1 1 over 6 

Jawaban:

Berdasarkan sifat bilangan berpangkat negatif yaitu a to the power of negative n end exponent equals 1 over a to the power of n spacemaka open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent equals 1 over open parentheses 2 over 3 close parentheses to the power of 4. Berdasarkan definisi bilangan berpangkat maka open parentheses 2 over 3 close parentheses to the power of 4 equals 2 over 3 cross times 2 over 3 cross times 2 over 3 cross times 2 over 3 spacesehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell 1 over open parentheses 2 over 3 close parentheses to the power of 4 end cell row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell fraction numerator 1 over denominator begin display style 2 over 3 end style cross times begin display style 2 over 3 end style cross times begin display style 2 over 3 end style cross times begin display style 2 over 3 end style end fraction end cell row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell fraction numerator 1 over denominator begin display style 16 over 81 end style end fraction end cell row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell 1 divided by 16 over 81 end cell row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell 1 cross times 81 over 16 end cell row cell open parentheses 2 over 3 close parentheses to the power of negative 4 end exponent end cell equals cell 81 over 16 end cell end table


Oleh karena itu, tidak ada opsi jawaban yang benar. Jadi jawaban yang tepat adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 81 over 16. end cell end table

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