Pertanyaan

Jika k 3 = 4 5 × 4 6 2 1 × 2 2 × 2 3 × 2 7 , maka nilai k = . . . .

Jika $k^{3} = \frac{2 ^{1} \times 2 ^{2} \times 2 ^{3} \times 2 ^{7}}{4 ^{5} \times 4 ^{6}}$ , maka nilai $k$ = . . . .

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D

Pembahasan

Jadi, jawaban yang tepat adalah D

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell k cubed end cell equals cell fraction numerator 2 to the power of 1 cross times 2 squared cross times 2 cubed cross times 2 to the power of 7 over denominator 4 to the power of 5 cross times 4 to the power of 6 end fraction end cell row cell k cubed end cell equals cell 2 to the power of 1 plus 2 plus 3 plus 7 end exponent over 4 to the power of 5 plus 6 end exponent end cell row cell k cubed end cell equals cell 2 to the power of 13 over 4 to the power of 11 end cell row cell k cubed end cell equals cell fraction numerator 2 to the power of 13 over denominator 2 to the power of 11 cross times 2 to the power of 11 end fraction end cell row cell k cubed end cell equals cell fraction numerator 2 to the power of up diagonal strike 13 space space 2 end exponent over denominator 2 to the power of 11 cross times up diagonal strike 2 to the power of 11 end strike end fraction end cell row cell k cubed end cell equals cell 2 squared over 2 to the power of 11 end cell row cell k cubed end cell equals cell 2 to the power of negative 9 end exponent end cell row k equals cell 2 to the power of fraction numerator negative 9 over denominator 3 end fraction end exponent end cell row k equals cell 2 to the power of negative 3 end exponent end cell row k equals cell 1 over 2 cubed end cell row k equals cell 1 over 8 end cell end table end style$

Jadi, jawaban yang tepat adalah D