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Pertanyaan

Diketahui vektor a with rightwards arrow on top equals open parentheses table row 2 row cell negative 3 end cell row 1 end table close parentheses space dan space b with rightwards arrow on top equals open parentheses table row 1 row cell negative 2 end cell row 3 end table close parentheses. Nilai sinus sudut antara vektor a with rightwards arrow on top space dan space b with rightwards arrow on top adalah.....

  1. 5 over 7

  2. 11 over 4

  3. fraction numerator 5 square root of 3 over denominator 14 end fraction

  4. 5 over 11 square root of 3

  5. fraction numerator 2 square root of 6 over denominator 7 end fraction

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

Ingat space rumus space perkalian space titik space pada space vektor space colon  straight a with rightwards arrow on top. straight b with rightwards arrow on top equals open vertical bar straight a with rightwards arrow on top close vertical bar open vertical bar straight b with rightwards arrow on top close vertical bar cosα  open parentheses table row 2 row cell negative 3 end cell row 1 end table close parentheses. open parentheses table row 1 row cell negative 2 end cell row 3 end table close parentheses equals square root of 2 squared plus open parentheses negative 3 close parentheses squared plus 1 squared end root square root of 1 squared plus open parentheses negative 2 close parentheses squared plus open parentheses 3 close parentheses squared end root cosα  2 plus 6 plus 3 equals square root of 14 square root of 14 cosα  11 equals 14 cosα  Berarti comma space cosα equals 11 over 14  Perhatikan space segitiga

Maka space sinα equals fraction numerator 5 square root of 3 over denominator 14 end fraction

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