Iklan

Iklan

Pertanyaan

Diketahui vektor u = ⎝ ⎛ ​ 4 3 − 8 ​ ⎠ ⎞ ​ dan v = ⎝ ⎛ ​ a − 5 − 2 ​ ⎠ ⎞ ​ . Jika hasil u ⋅ v = − 11 , tentukan: b. Hasil v ⋅ ( u − v )

Diketahui vektor  Jika hasil  tentukan:

b. Hasil           space space                      undefined   space   space undefined  

Iklan

A. Tegar

Master Teacher

Jawaban terverifikasi

Jawaban

hasilnya adalah

hasilnya adalah begin mathsize 14px style negative 49. end style 

Iklan

Pembahasan

Perhatikan penghitungan berikut! Jadi, hasilnya adalah

Perhatikan penghitungan berikut!

 begin mathsize 14px style u with rightwards arrow on top times v with rightwards arrow on top space space space space space equals open parentheses table row 4 row 3 row cell negative 8 end cell end table close parentheses times open parentheses table row a row cell negative 5 end cell row cell negative 2 end cell end table close parentheses minus 11 space space space space space equals 4 a minus 15 plus 16 minus 11 space space space space space equals 4 a plus 1 minus 11 minus 1 equals 4 a minus 12 space space space space space equals 4 a fraction numerator negative 12 over denominator 4 end fraction space space space space equals a minus 3 space space space space space space space equals a  v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals open parentheses table row a row cell negative 5 end cell row cell negative 2 end cell end table close parentheses times open parentheses open parentheses table row 4 row 3 row cell negative 8 end cell end table close parentheses minus open parentheses table row a row cell negative 5 end cell row cell negative 2 end cell end table close parentheses close parentheses v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals open parentheses table row a row cell negative 5 end cell row cell negative 2 end cell end table close parentheses times open parentheses table row cell 4 minus a end cell row 8 row cell negative 6 end cell end table close parentheses v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals a left parenthesis 4 minus a right parenthesis plus left parenthesis negative 5 right parenthesis left parenthesis 8 right parenthesis plus left parenthesis negative 2 right parenthesis left parenthesis negative 6 right parenthesis v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals open parentheses negative 3 close parentheses left parenthesis 4 minus open parentheses negative 3 close parentheses right parenthesis plus left parenthesis negative 5 right parenthesis left parenthesis 8 right parenthesis plus left parenthesis negative 2 right parenthesis left parenthesis negative 6 right parenthesis v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals negative 21 minus 40 plus 12 v with rightwards arrow on top times open parentheses u with rightwards arrow on top minus v with rightwards arrow on top close parentheses equals negative 49   end style 

Jadi, hasilnya adalah begin mathsize 14px style negative 49. end style 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

91

Iklan

Iklan

Pertanyaan serupa

Diketahui vektor a = 6 x i + 2 x j ​ − 8 k , b = − 4 i + 8 j ​ + 10 k ,dan c = − 2 i + 3 j ​ − 5 k . Jika vektor a tegak lurus b , maka vektor a − c = ...

33

4.8

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia