Roboguru

Diketahui vektor . Hitunglah vektor satuan dari vektor .

Pertanyaan

Diketahui vektor b with rightwards arrow on top equals open parentheses 3 comma space minus 4 close parentheses. Hitunglah vektor satuan dari vektor b with rightwards arrow on top.

Pembahasan Soal:

Vektor satuan.

vektor space satuan space b with rightwards arrow on top equals fraction numerator 1 over denominator open vertical bar b with rightwards arrow on top close vertical bar end fraction b with rightwards arrow on top

Diketahui vektor b with rightwards arrow on top equals open parentheses 3 comma space minus 4 close parentheses. Akan ditentukan vektor satuan dari vektor b with rightwards arrow on top.

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell vektor space satuan space b with rightwards arrow on top end cell equals cell fraction numerator 1 over denominator open vertical bar b with rightwards arrow on top close vertical bar end fraction b with rightwards arrow on top end cell row blank equals cell fraction numerator 1 over denominator square root of open parentheses 3 close parentheses squared plus open parentheses negative 4 close parentheses squared end root end fraction cross times open parentheses 3 comma space minus 4 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 9 plus 16 end root end fraction cross times open parentheses 3 comma space minus 4 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 25 end fraction cross times open parentheses 3 comma space minus 4 close parentheses end cell row blank equals cell 1 fifth cross times open parentheses 3 comma space minus 4 close parentheses end cell row cell vektor space satuan space b with rightwards arrow on top end cell equals cell open parentheses 3 over 5 comma space minus 4 over 5 close parentheses end cell end table

Jadi, diperoleh vektor satuan dari vektor b with rightwards arrow on top adalah open parentheses 3 over 5 comma space minus 4 over 5 close parentheses.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 06 Mei 2021

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