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Diketahui vektor  dan . Jika vektor  memenuhi pers...

Diketahui vektor begin mathsize 14px style straight p with rightwards arrow on top equals open parentheses table attributes columnalign right end attributes row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses end style dan begin mathsize 14px style straight q with rightwards arrow on top equals open parentheses table attributes columnalign right end attributes row 2 row 5 row cell negative 3 end cell end table close parentheses end style. Jika vektor begin mathsize 14px style straight r with rightwards arrow on top end style memenuhi persamaan begin mathsize 14px style 2 straight r with rightwards arrow on top plus 5 straight p with rightwards arrow on top equals 3 straight q with rightwards arrow on top plus 4 straight r with rightwards arrow on top end style, hasil operasi begin mathsize 14px style straight p with rightwards arrow on top plus straight q with rightwards arrow on top plus 2 straight r with rightwards arrow on top end style adalah undefined

  1. begin mathsize 14px style open parentheses table row 14 row 22 row 12 end table close parentheses end style

  2. begin mathsize 14px style open parentheses table row 14 row 22 row 0 end table close parentheses end style

  3. begin mathsize 14px style open parentheses table attributes columnalign right end attributes row 14 row cell negative 22 end cell row 0 end table close parentheses end style

  4. begin mathsize 14px style open parentheses table attributes columnalign right end attributes row cell negative 14 end cell row 22 row 0 end table close parentheses end style

  5. begin mathsize 14px style open parentheses table attributes columnalign right end attributes row cell negative 14 end cell row 22 row 12 end table close parentheses end style

Jawaban:

Secara aljabar dua vektor dapat dijumlahkan dengan cara sebagai beikut.

begin mathsize 14px style straight a with rightwards arrow on top plus straight b with rightwards arrow on top equals open parentheses table row cell x subscript straight a end cell row cell y subscript straight a end cell row cell z subscript straight a end cell end table close parentheses plus open parentheses table row cell x subscript straight b end cell row cell y subscript straight b end cell row cell z subscript straight b end cell end table close parentheses equals open parentheses table row cell x subscript straight a plus x subscript straight b end cell row cell y subscript straight a plus y subscript straight b end cell row cell z subscript straight a plus z subscript straight b end cell end table close parentheses end style

Sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 straight r with rightwards arrow on top plus 5 straight p with rightwards arrow on top end cell equals cell 3 straight q with rightwards arrow on top plus 4 straight r with rightwards arrow on top end cell row cell 2 straight r with rightwards arrow on top plus 5 open parentheses table attributes columnalign right end attributes row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses end cell equals cell 3 open parentheses table attributes columnalign right end attributes row 2 row 5 row cell negative 3 end cell end table close parentheses plus 4 straight r with rightwards arrow on top end cell row cell 2 straight r with rightwards arrow on top plus open parentheses table attributes columnalign right end attributes row 15 row cell negative 10 end cell row cell negative 5 end cell end table close parentheses end cell equals cell open parentheses table attributes columnalign right end attributes row 6 row 15 row cell negative 9 end cell end table close parentheses plus 4 straight r with rightwards arrow on top end cell row cell open parentheses table attributes columnalign right end attributes row 15 row cell negative 10 end cell row cell negative 5 end cell end table close parentheses plus open parentheses table attributes columnalign right end attributes row cell negative 6 end cell row cell negative 15 end cell row 9 end table close parentheses end cell equals cell 4 straight r with rightwards arrow on top minus 2 straight r with rightwards arrow on top end cell row cell open parentheses table attributes columnalign right end attributes row 9 row cell negative 25 end cell row 4 end table close parentheses end cell equals cell 2 straight r with rightwards arrow on top end cell row cell straight r with rightwards arrow on top end cell equals cell open parentheses table attributes columnalign center end attributes row cell 9 over 2 end cell row cell negative 25 over 2 end cell row 2 end table close parentheses end cell end table end style

Maka hasil operasi begin mathsize 14px style straight p with rightwards arrow on top plus straight q with rightwards arrow on top plus 2 straight r with rightwards arrow on top end style adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight p with rightwards arrow on top plus straight q with rightwards arrow on top plus 2 straight r with rightwards arrow on top end cell equals cell open parentheses table attributes columnalign right end attributes row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses plus open parentheses table attributes columnalign right end attributes row 2 row 5 row cell negative 3 end cell end table close parentheses plus 2 open parentheses table attributes columnalign center end attributes row cell 9 over 2 end cell row cell negative 25 over 2 end cell row 2 end table close parentheses end cell row blank equals cell open parentheses table attributes columnalign right end attributes row 5 row 3 row cell negative 4 end cell end table close parentheses plus open parentheses table attributes columnalign right end attributes row 9 row cell negative 25 end cell row 4 end table close parentheses end cell row blank equals cell open parentheses table attributes columnalign right end attributes row 14 row cell negative 22 end cell row 0 end table close parentheses end cell end table end style

Jadi, jawaban yang tepat adalah C.

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