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Diketahui m = i + 2 j ​ − 3 k , n = 3 i − j ​ − 3 k serta p ​ = 2 i − 3 j ​ + 5 k . Proyeksi m pada n + p ​ adalah...

Diketahui serta . Proyeksi pada  adalah...   

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hasil proyeksinya adalah

hasil proyeksinya adalah begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell i with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 4 over 5 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell j with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 over 5 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell k with rightwards arrow on top end cell end table end style  

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Sebelum kita mencari hasil proyeksi dari Proyeksi pada , terlebih dahulu kita mencari dan : Maka, hasil proyeksi dari Proyeksi pada (z) adalah: z ​ = = = = = = ​ ( ∣ n + p ​ ∣ 2 m ⋅ ( n + p ​ ) ​ ) ( n + p ​ ) ( ( 5 2 + ( − 4 ) 2 + 2 2 ​ ) 2 1 ⋅ 5 + 2 ⋅ ( − 4 ) + ( − 3 ) 2 ​ ) ⎝ ⎛ ​ 5 − 4 2 ​ ⎠ ⎞ ​ 45 − 9 ​ ⎝ ⎛ ​ 5 − 4 2 ​ ⎠ ⎞ ​ 5 − 1 ​ ⎝ ⎛ ​ 5 − 4 2 ​ ⎠ ⎞ ​ ⎝ ⎛ ​ − 1 5 4 ​ − 5 2 ​ ​ ⎠ ⎞ ​ − i + 5 4 ​ j ​ − 5 2 ​ k ​ Jadi, hasil proyeksinya adalah

Sebelum kita mencari hasil proyeksi dari Proyeksi begin mathsize 14px style straight m with rightwards arrow on top end style pada begin mathsize 14px style straight n with rightwards arrow on top plus straight p with rightwards arrow on top end style , terlebih dahulu kita mencari  begin mathsize 14px style straight n with rightwards arrow on top plus straight p with rightwards arrow on top end style dan  :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight n with rightwards arrow on top plus straight p with rightwards arrow on top end cell equals cell open parentheses table row 3 row cell negative 1 end cell row cell negative 3 end cell end table close parentheses plus open parentheses table row 2 row cell negative 3 end cell row 5 end table close parentheses end cell row cell straight n with rightwards arrow on top plus straight p with rightwards arrow on top end cell equals cell open parentheses table row 5 row cell negative 4 end cell row 2 end table close parentheses end cell row cell straight n with rightwards arrow on top plus straight p with rightwards arrow on top end cell equals cell 5 straight i with rightwards arrow on top minus 4 straight j with rightwards arrow on top plus 2 straight k with rightwards arrow on top end cell end table end style

Maka, hasil proyeksi dari Proyeksi begin mathsize 14px style straight m with rightwards arrow on top end style pada begin mathsize 14px style straight n with rightwards arrow on top plus straight p with rightwards arrow on top end style (z) adalah:

Jadi, hasil proyeksinya adalah begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell i with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 4 over 5 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell j with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 over 5 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell k with rightwards arrow on top end cell end table end style  

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Diketahui kubus satuan ABCD.EFGH. Misalkan vektor-vektor AB = i = ( 1 , 0 , 0 ) ; AD = j ​ = ( 0 , 1 , 0 ) ; AE = k = ( 0 , 0 , 1 ) . Titik P adalah titik pusat sisi BCGF. Tentukan proyeksi FP pada ve...

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