Iklan

Iklan

Pertanyaan

Diketahui panjang komponen proyeksi vektor a pada vektor b adalah 6. Jika a = x i − 4 j ​ + y k , ∣ ∣ ​ a ∣ ∣ ​ = 89 ​ dan b = − 2 i + j ​ + 2 k serta ∠ ( a , b ) lancip, tentukan nilai dari x 2 + 2 y 2 !

Diketahui panjang komponen proyeksi vektor    pada vektor  adalah 6. Jika  dan  serta  lancip, tentukan nilai dari  ! space 

Iklan

B. Hary

Master Teacher

Jawaban terverifikasi

Jawaban

nilai dari atau nilai dari .

nilai dari x squared plus 2 y squared equals 82 atau nilai dari x squared plus 2 y squared equals 137.space space space space  

Iklan

Pembahasan

Perhatikan penghitungan berikut! Jadi, nilai dari atau nilai dari .

Perhatikan penghitungan berikut!

  table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell Panjang space komponen space vektor space a with rightwards arrow on top space pada space b with rightwards arrow on top end cell row 6 equals cell fraction numerator a with rightwards arrow on top bullet b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar end fraction end cell row 6 equals cell fraction numerator open parentheses table row x row cell negative 4 end cell row y end table close parentheses bullet open parentheses table row cell negative 2 end cell row 1 row 2 end table close parentheses over denominator square root of left parenthesis negative 2 right parenthesis squared plus 1 squared plus 2 squared end root end fraction end cell row 6 equals cell fraction numerator negative 2 x minus 4 plus 2 y over denominator 3 end fraction end cell row 18 equals cell negative 2 x minus 4 plus 2 y end cell row 22 equals cell negative 2 x plus 2 y end cell row cell negative 11 end cell equals cell x minus y end cell row x equals cell y minus 11... left parenthesis i right parenthesis end cell row blank blank blank row blank blank blank row cell open vertical bar a with rightwards arrow on top close vertical bar end cell equals cell square root of x squared plus open parentheses negative 4 close parentheses squared plus y squared end root end cell row cell square root of 89 end cell equals cell square root of x squared plus 16 plus y squared end root end cell row 89 equals cell x squared plus 16 plus y squared end cell row 73 equals cell x squared plus y squared end cell row 73 equals cell left parenthesis y minus 11 right parenthesis squared plus y squared space end cell row 73 equals cell y squared minus 22 y plus 121 plus y squared end cell row 73 equals cell 2 y squared minus 22 y plus 121 end cell row 0 equals cell 2 y squared minus 22 y plus 48 end cell row 0 equals cell open parentheses y minus 8 close parentheses open parentheses y minus 3 close parentheses end cell row y equals cell 8 space atau space y equals 3 end cell row blank blank blank row cell ketika space y end cell equals cell 8 rightwards arrow x equals 8 minus 11 equals negative 3 end cell row blank blank cell sehingga colon end cell row cell x squared plus 2 y squared end cell equals cell open parentheses negative 3 close parentheses squared plus 2 open parentheses 8 close parentheses squared equals 137 end cell row blank blank blank row cell ketika space y end cell equals cell 3 space space space rightwards arrow x equals 3 minus 11 equals negative 8 end cell row blank blank cell sehingga colon end cell row cell x squared plus 2 y squared end cell equals cell open parentheses negative 8 close parentheses squared plus 2 open parentheses 3 close parentheses squared equals 82 end cell row blank blank blank row blank blank blank row blank blank blank end table       

Jadi, nilai dari x squared plus 2 y squared equals 82 atau nilai dari x squared plus 2 y squared equals 137.space space space space  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

112

Iklan

Iklan

Pertanyaan serupa

Diketahui vektor p ⇀ ​ = ( 2 5 ​ ) dan q ⇀ ​ = ( 2 4 ​ ) Tentukan nilai dari 3 ( p ⇀ ​ + q ⇀ ​ ) = ...

1

3.8

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia