Pertanyaan

Diketahui matriks A= ( 2 5 3 4 ) , B = ( − 1 0 4 2 ) , dan X=A+B. Invers matriks X adalah ....

Diketahui matriks A= $(2534), B = (- 10 42)$ , dan X=A+B. Invers matriks X adalah ....

$negative fraction numerator begin display style 1 end style over denominator begin display style 29 end style end fraction open parentheses table row cell 6 space space space space space minus space 5 end cell row cell negative 7 space space space space 1 end cell end table close parentheses$
$fraction numerator begin display style 1 end style over denominator begin display style 29 end style end fraction open parentheses table row cell 6 space space space space space space minus 5 end cell row cell negative 7 space space space space 1 end cell end table close parentheses$
$fraction numerator begin display style 1 end style over denominator begin display style 29 end style end fraction open parentheses table row cell 6 space space space space space minus space 5 end cell row cell negative 7 space space space space minus 1 end cell end table close parentheses$

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

$X equals space A plus B X equals open parentheses table row cell 2 space space space 5 end cell row cell 3 space space space space space 4 end cell end table close parentheses plus open parentheses table row cell negative 1 space space space space 0 end cell row cell 4 space space space space space space 2 end cell end table close parentheses equals open parentheses table row cell 1 space space space space space 5 end cell row cell 7 space space space space 6 end cell end table close parentheses X to the power of negative 1 end exponent equals fraction numerator 1 over denominator open vertical bar X close vertical bar end fraction A d j left parenthesis X right parenthesis J i k a space X space equals space open parentheses table row cell a space space space space b end cell row cell c space space space space space d end cell end table close parentheses comma space m a k a A d j space left parenthesis X right parenthesis equals space open parentheses table row cell d space space space space space minus b end cell row cell negative c space space space space space a end cell end table close parentheses space d a n space open vertical bar X close vertical bar equals space a d minus b c S e h i n g g a A d j left parenthesis X right parenthesis equals space open parentheses table row cell d space space space space space minus b end cell row cell negative c space space space space space a end cell end table close parentheses space equals space open parentheses table row cell 6 space space space space minus 5 end cell row cell negative 7 space space space space space 1 end cell end table close parentheses D a n open vertical bar X close vertical bar equals space a d minus b c equals 6 minus 35 M a k a comma X to the power of negative 1 end exponent equals fraction numerator 1 over denominator 6 minus 35 end fraction open parentheses table row cell 6 space space space space minus 5 end cell row cell negative 7 space space space space space 1 end cell end table close parentheses equals negative 1 over 29 open parentheses table row cell 6 space space space space minus 5 end cell row cell negative 7 space space space space 1 end cell end table close parentheses$