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Diketahui . Jika menyatakan determinan dari matriks P , maka

Diketahui begin mathsize 14px style P equals open parentheses table row 1 2 row cell negative 1 end cell 1 end table close parentheses end style . Jika begin mathsize 14px style open vertical bar P close vertical bar end style  menyatakan determinan dari matriks P, maka begin mathsize 14px style open vertical bar P to the power of negative 1 end exponent close vertical bar plus open vertical bar P to the power of negative 1 end exponent close vertical bar squared plus open vertical bar P to the power of negative 1 end exponent close vertical bar cubed plus open vertical bar P to the power of negative 1 end exponent close vertical bar to the power of 4 plus... equals.... end style 

  1. begin mathsize 14px style 8 end style 

  2. size 14px 3 

  3. size 14px 2 

  4. begin mathsize 14px style 1 end style 

  5. undefined 

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Perhatikan bahwa Maka Perhatikan bahwa bentuk tersebut membentuk deret geometri tak hingga dengan dan , sehingga Jadi, jawaban yang tepat adalah E.

Perhatikan bahwa

begin mathsize 14px style open vertical bar P to the power of negative 1 end exponent close vertical bar equals fraction numerator 1 over denominator open vertical bar P close vertical bar end fraction open vertical bar P to the power of negative 1 end exponent close vertical bar equals fraction numerator 1 over denominator 1 times 1 minus open parentheses negative 1 close parentheses times 2 end fraction open vertical bar P to the power of negative 1 end exponent close vertical bar equals fraction numerator 1 over denominator 1 plus 2 end fraction open vertical bar P to the power of negative 1 end exponent close vertical bar equals 1 third end style 

Maka

begin mathsize 14px style open vertical bar P to the power of negative 1 end exponent close vertical bar plus open vertical bar P to the power of negative 1 end exponent close vertical bar squared plus open vertical bar P to the power of negative 1 end exponent close vertical bar cubed plus open vertical bar P to the power of negative 1 end exponent close vertical bar to the power of 4 plus horizontal ellipsis equals open parentheses 1 third close parentheses plus open parentheses 1 third close parentheses squared plus open parentheses 1 third close parentheses cubed plus open parentheses 1 third close parentheses to the power of 4 plus horizontal ellipsis end style 

Perhatikan bahwa bentuk tersebut membentuk deret geometri tak hingga dengan begin mathsize 14px style straight a equals 1 third end style dan begin mathsize 14px style straight r equals 1 third end style, sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell S subscript infinity end cell equals cell open parentheses 1 third close parentheses plus open parentheses 1 third close parentheses squared plus open parentheses 1 third close parentheses cubed plus open parentheses 1 third close parentheses to the power of 4 plus horizontal ellipsis end cell row blank equals cell fraction numerator a over denominator 1 minus r end fraction end cell row blank equals cell fraction numerator 1 third over denominator 1 minus 1 third end fraction end cell row blank equals cell fraction numerator 1 third over denominator 2 over 3 end fraction end cell row blank equals cell 1 half end cell end table end style 

Jadi, jawaban yang tepat adalah E.

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