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Jawaban terverifikasi

Pembahasan

Maka, jawaban yang tepat adalah A.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as h rightwards arrow 0 of invisible function application fraction numerator f open parentheses x plus h close parentheses minus f left parenthesis x right parenthesis over denominator h end fraction end cell equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 2 open parentheses x plus h close parentheses squared plus 5 open parentheses x plus h close parentheses minus left parenthesis 2 x squared plus 5 x right parenthesis over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 2 open parentheses x squared plus 2 h x plus h squared close parentheses plus down diagonal strike 5 x end strike plus 5 h minus 2 x squared minus down diagonal strike 5 x end strike over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator down diagonal strike 2 x squared end strike plus 4 h x plus 2 h squared plus 5 h down diagonal strike negative 2 x squared end strike over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 4 h x plus 2 h squared plus 5 h over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator up diagonal strike h open parentheses 4 x plus 2 h plus 5 close parentheses over denominator up diagonal strike h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application open parentheses 4 x plus 2 h plus 5 close parentheses end cell row blank equals cell 4 x plus 2.0 plus 5 end cell row blank equals cell 4 x plus 5 end cell end table end style$

Maka, jawaban yang tepat adalah A.