Pertanyaan

Diketahui fungsi maka hasil dari adalah ...

Diketahui fungsi maka hasil dari $begin mathsize 14px style limit as h rightwards arrow 0 of invisible function application fraction numerator f open parentheses x plus h close parentheses minus f left parenthesis x right parenthesis over denominator h end fraction end style$ adalah ...

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Jawaban terverifikasi

Pembahasan

Maka, jawaban yang tepat adalah C.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as h rightwards arrow 0 of invisible function application fraction numerator f open parentheses x plus h close parentheses minus f left parenthesis x right parenthesis over denominator h end fraction end cell equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 3 open parentheses x plus h close parentheses squared minus left parenthesis 3 x squared right parenthesis over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 3 open parentheses x squared plus 2 h x plus h squared close parentheses minus 3 x squared over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator up diagonal strike 3 x squared end strike plus 6 h x plus 3 h squared up diagonal strike negative 3 x squared end strike over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator 6 h x plus 3 h squared over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application fraction numerator h left parenthesis 6 x plus 3 h right parenthesis over denominator h end fraction end cell row blank equals cell limit as h rightwards arrow 0 of invisible function application 6 x plus 3 h end cell row blank equals cell 6 x end cell end table end style$

Maka, jawaban yang tepat adalah C.