Iklan

Iklan

Pertanyaan

Diketahui fungsi f ( x ) = x 3 dan g ( x ) = 3 x − 4 . Jika a = ( g − 1 ∘ f − 1 ) ( 8 ) , maka nilai ( f − 1 ∘ g − 1 ) ( 10 a ) adalah ...

Diketahui fungsi  dan . Jika , maka nilai  adalah ...

Iklan

S. Nur

Master Teacher

Jawaban terverifikasi

Iklan

Pembahasan

Tentukan invers fungsinya terlebih dahulu. Kemudian dari fungsi-fungsi invers tersebut gunakan rumus fungsi komposisi untuk mengetahui nilai . Kemudian diperoleh: Maka, nilai adalah .

Tentukan invers fungsinya terlebih dahulu.

table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell x cubed end cell row y equals cell x cubed end cell row x equals cell cube root of y end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell cube root of x end cell row blank blank blank row cell g open parentheses x close parentheses end cell equals cell 3 x minus 4 end cell row y equals cell 3 x minus 4 end cell row x equals cell fraction numerator y plus 4 over denominator 3 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x plus 4 over denominator 3 end fraction end cell end table

Kemudian dari fungsi-fungsi invers tersebut gunakan rumus fungsi komposisi untuk mengetahui nilai a.

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses 8 close parentheses end cell equals a row cell g to the power of negative 1 end exponent open parentheses f to the power of negative 1 end exponent open parentheses 8 close parentheses close parentheses end cell equals a row cell g to the power of negative 1 end exponent open parentheses cube root of 8 close parentheses end cell equals a row cell fraction numerator cube root of 8 plus 4 over denominator 3 end fraction end cell equals a row cell fraction numerator 2 plus 4 over denominator 3 end fraction end cell equals a row cell 6 over 3 end cell equals a row 2 equals a end table

Kemudian diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f to the power of negative 1 end exponent ring operator g to the power of negative 1 end exponent close parentheses open parentheses 10 a close parentheses end cell equals cell f to the power of negative 1 end exponent open parentheses g to the power of negative 1 end exponent open parentheses 10 open parentheses 2 close parentheses close parentheses close parentheses end cell row blank equals cell f to the power of negative 1 end exponent open parentheses g to the power of negative 1 end exponent open parentheses 20 close parentheses close parentheses end cell row blank equals cell f to the power of negative 1 end exponent open parentheses fraction numerator 20 plus 4 over denominator 3 end fraction close parentheses end cell row blank equals cell cube root of fraction numerator 20 plus 4 over denominator 3 end fraction end root end cell row blank equals cell cube root of 24 over 3 end root end cell row blank equals cell cube root of 8 end cell row blank equals 2 end table

Maka, nilai open parentheses f to the power of negative 1 end exponent ring operator g to the power of negative 1 end exponent close parentheses open parentheses 10 a close parentheses adalah 2.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Iklan

Iklan

Pertanyaan serupa

Diketahui dan c. Apakah ( f − 1 ∘ g − 1 ) ( x ) = ( g − 1 ∘ f − 1 ) ( x ) ?

1

4.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia