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Diketahui  dengan sudut  di kuadran III. Nilai  adalah ....

Pertanyaan

Diketahui begin mathsize 14px style cos space A equals negative 2 over 5 square root of 5 end style dengan sudut begin mathsize 14px style A end style di kuadran III. Nilai begin mathsize 14px style sin space A end style adalah ....

Pembahasan Soal:

Diketahui begin mathsize 14px style cos space A equals negative 2 over 5 square root of 5 end style atau begin mathsize 14px style cos space A equals x over r equals fraction numerator negative 2 square root of 5 over denominator 5 end fraction end style , sehingga begin mathsize 14px style x equals negative 2 square root of 5 end style dan begin mathsize 14px style r equals 5 end style.

   begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row y equals cell square root of r squared minus x squared end root end cell row blank equals cell square root of 5 squared minus open parentheses negative 2 square root of 5 close parentheses squared end root end cell row blank equals cell square root of 25 minus 20 end root end cell row blank equals cell square root of 5 end cell end table end style 

Sudut begin mathsize 14px style A end style di kuadran III, maka begin mathsize 14px style sin space A end style negatif.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell sin space A end cell equals cell negative y over r end cell row blank equals cell negative fraction numerator square root of 5 over denominator 5 end fraction end cell row blank equals cell negative 1 fifth square root of 5 end cell end table end style  

Jadi, nilai begin mathsize 14px style sin space A end style adalah begin mathsize 14px style negative 1 fifth square root of 5 end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 April 2021

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