Iklan

Iklan

Pertanyaan

Diketahui a = 1 ∑ 12 ​ a 2 = 650 dan a = 5 ∑ 16 ​ a = 126 . Tentukan nilai a = 1 ∑ 12 ​ ( 3 a − 2 ) 2 .

Diketahui  dan . Tentukan nilai 

Iklan

S. Yoga

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

nilai adalah 4.962

 nilai begin mathsize 14px style sum from a equals 1 to 12 of left parenthesis 3 a minus 2 right parenthesis squared end style adalah 4.962

Iklan

Pembahasan

Jadi,nilai adalah 4.962

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell sum from a equals 1 to 12 of left parenthesis 3 a minus 2 right parenthesis squared end cell equals cell sum from a equals 1 to 12 of left parenthesis 9 a squared minus 12 a plus 4 right parenthesis end cell row blank equals cell sum from a equals 1 to 12 of 9 a squared minus sum from a equals 1 to 12 of 12 a plus sum from a equals 1 to 12 of 4 end cell row blank equals cell 9 sum from a equals 1 to 12 of a squared minus sum from a equals 1 plus 4 to 12 plus 4 of 12 left parenthesis a minus 4 right parenthesis plus sum from a equals 1 to 12 of 4 end cell row blank equals cell 9 sum from a equals 1 to 12 of a squared minus sum from a equals 5 to 16 of 12 a minus 48 plus sum from a equals 1 to 12 of 4 end cell row blank equals cell 9 sum from a equals 1 to 12 of a squared minus 12 sum from a equals 5 to 16 of a plus sum from a equals 5 to 16 of 48 plus sum from a equals 1 to 12 of 4 end cell row blank equals cell 9 left parenthesis 650 right parenthesis minus 12 left parenthesis 126 right parenthesis plus left parenthesis 16 minus 5 plus 1 right parenthesis 48 plus left parenthesis 12 minus 1 plus 1 right parenthesis 4 end cell row blank equals cell 4.962 end cell end table end style  

Jadi, nilai begin mathsize 14px style sum from a equals 1 to 12 of left parenthesis 3 a minus 2 right parenthesis squared end style adalah 4.962

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Velincia Yogananta

Tidak sama persis

Iklan

Iklan

Pertanyaan serupa

Diketahui . Nilai p yang memenuhi persamaan tersebut adalah ….

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia