Pertanyaan

Diketahui f ( x ) = 3 x − 6 dan ( g ∘ f ) − 1 ( x ) = 4 x + 12 . Maka, g − 1 ( x ) = ....

Diketahui  dan . Maka,  ....

  1. begin mathsize 14px style 12 x plus 30 end style space space 

  2. size 14px 12 size 14px x size 14px minus size 14px 12 space space 

  3. begin mathsize 14px style 4 over 3 x plus 6 end style  space space 

  4. begin mathsize 14px style 4 over 3 x minus 12 end style  space space 

  5. begin mathsize 14px style 3 over 4 x minus 12 end style  space space 

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

Pembahasan

Pertama, kita cari Sehingga Jadi, jawaban yang tepat adalah A.

Pertama, kita cari begin mathsize 14px style f to the power of negative 1 end exponent end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell 3 x minus 6 end cell row y equals cell 3 x minus 6 end cell row cell y plus 6 end cell equals cell 3 x end cell row cell fraction numerator y plus 6 over denominator 3 end fraction end cell equals x row cell y over 3 plus 2 end cell equals x row blank blank blank row cell f open parentheses x close parentheses end cell equals y row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals x row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals cell y over 3 plus 2 end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell x over 3 plus 2 end cell end table end style 

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 4 x plus 12 end cell row cell open parentheses f to the power of negative 1 end exponent ring operator g to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end cell equals cell 4 x plus 12 end cell row cell f to the power of negative 1 end exponent open parentheses g to the power of negative 1 end exponent open parentheses x close parentheses close parentheses end cell equals cell 4 x plus 12 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction plus 2 end cell equals cell 4 x plus 12 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction end cell equals cell 4 x plus 12 minus 2 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction end cell equals cell 4 x plus 10 end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 3 open parentheses 4 x plus 10 close parentheses end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 12 x plus 30 end cell end table end style 

Jadi, jawaban yang tepat adalah A.

23

5.0 (1 rating)

Iklan

Pertanyaan serupa

Perhatikan fungsi komposisi berikut! Nilai dari adalah ....

67

0.0

Jawaban terverifikasi

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia