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Pertanyaan

Diketahui f ( x ) = 3 x − 6 dan ( g ∘ f ) − 1 ( x ) = 4 x + 12 . Maka, g − 1 ( x ) = ....

Diketahui  dan . Maka,  ....

  1. begin mathsize 14px style 12 x plus 30 end style space space 

  2. size 14px 12 size 14px x size 14px minus size 14px 12 space space 

  3. begin mathsize 14px style 4 over 3 x plus 6 end style  space space 

  4. begin mathsize 14px style 4 over 3 x minus 12 end style  space space 

  5. begin mathsize 14px style 3 over 4 x minus 12 end style  space space 

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

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Pembahasan

Pertama, kita cari Sehingga Jadi, jawaban yang tepat adalah A.

Pertama, kita cari begin mathsize 14px style f to the power of negative 1 end exponent end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell 3 x minus 6 end cell row y equals cell 3 x minus 6 end cell row cell y plus 6 end cell equals cell 3 x end cell row cell fraction numerator y plus 6 over denominator 3 end fraction end cell equals x row cell y over 3 plus 2 end cell equals x row blank blank blank row cell f open parentheses x close parentheses end cell equals y row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals x row cell f to the power of negative 1 end exponent open parentheses y close parentheses end cell equals cell y over 3 plus 2 end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell x over 3 plus 2 end cell end table end style 

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 4 x plus 12 end cell row cell open parentheses f to the power of negative 1 end exponent ring operator g to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end cell equals cell 4 x plus 12 end cell row cell f to the power of negative 1 end exponent open parentheses g to the power of negative 1 end exponent open parentheses x close parentheses close parentheses end cell equals cell 4 x plus 12 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction plus 2 end cell equals cell 4 x plus 12 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction end cell equals cell 4 x plus 12 minus 2 end cell row cell fraction numerator g to the power of negative 1 end exponent open parentheses x close parentheses over denominator 3 end fraction end cell equals cell 4 x plus 10 end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 3 open parentheses 4 x plus 10 close parentheses end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell 12 x plus 30 end cell end table end style 

Jadi, jawaban yang tepat adalah A.

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