Pertanyaan

Diketahui f ( x ) = x − 1 − 4 x + 3 , x  = 1 dan g ( x ) = x + 2 . Maka ( g ∘ f ) − 1 ( x ) !

Diketahui $f (x) = \frac{- 4 x + 3}{x - 1}, x \neq = 1$ dan $g (x) = x + 2$ . Maka $(g \circ f)^{- 1} (x)$ !

$fraction numerator x plus 2 over denominator x plus 1 end fraction comma space x not equal to 1$
$fraction numerator x plus 1 over denominator x plus 2 end fraction comma space x not equal to negative 2$
$fraction numerator x minus 3 over denominator x minus 2 end fraction comma space x not equal to 2$
$fraction numerator x plus 3 over denominator x plus 2 end fraction comma space x not equal to negative 2$
$fraction numerator negative x plus 3 over denominator x minus 1 end fraction comma space x not equal to negative 1$

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Klaim

Y. Herlanda

Master Teacher

Mahasiswa/Alumni STKIP PGRI Jombang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Jadi, . Oleh karena itu, jawaban yang benar adalah B.

$table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell fraction numerator negative 4 x plus 3 over denominator x minus 1 end fraction comma space g open parentheses x close parentheses equals x plus 2 end cell row cell open parentheses g ring operator f close parentheses open parentheses x close parentheses end cell equals cell g open parentheses f open parentheses x close parentheses close parentheses end cell row blank equals cell x plus 2 end cell row blank equals cell fraction numerator negative 4 x plus 3 over denominator x minus 1 end fraction plus 2 end cell row blank equals cell fraction numerator negative 4 x plus 3 plus 2 x minus 2 over denominator x minus 1 end fraction end cell row blank equals cell fraction numerator negative 2 x plus 1 over denominator x minus 1 end fraction end cell row cell open parentheses g ring operator f close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x plus 1 over denominator x plus 2 end fraction comma space x not equal to negative 2 end cell end table$

Jadi, Error converting from MathML to accessible text. .

Oleh karena itu, jawaban yang benar adalah B.