Iklan

Pertanyaan

Diketahui Y = 40 − X 2 dan X = ( 3 1 ​ Y + 20 ) 2 1 ​ + 2 . Carilah perpotongan titik antara kedua persamaan tersebut!

Diketahui  dan . Carilah perpotongan titik antara kedua persamaan tersebut!

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

06

:

46

:

19

Klaim

Iklan

O. Rahmawati

Master Teacher

Mahasiswa/Alumni UIN Sunan Gunung Djati Bandung

Jawaban terverifikasi

Pembahasan

Subtitusikan persamaan ke persamaan Selesaikan persamaan kuadrat dengan rumus kuadratik yaitu Didapatkan Subtitusikan masing-masing ke persamaan untuk maka untuk maka Jadi, titik potong antara kedua persamaan tersebut adalah

  • Subtitusikan persamaan Y equals 40 minus X squared ke persamaan X equals open parentheses 1 third Y plus 20 close parentheses to the power of 1 half end exponent plus 2

table attributes columnalign right center left columnspacing 0px end attributes row X equals cell open parentheses 1 third open parentheses 40 minus X squared close parentheses plus 20 close parentheses to the power of 1 half end exponent plus 2 end cell row X equals cell open parentheses 40 over 3 minus 1 third X squared plus 20 close parentheses to the power of 1 half end exponent plus 2 end cell row X equals cell open parentheses negative 1 third X squared plus 100 over 3 close parentheses to the power of 1 half end exponent plus 2 end cell row cell X minus 2 end cell equals cell open parentheses negative 1 third X squared plus 100 over 3 close parentheses to the power of 1 half end exponent end cell row cell open parentheses X minus 2 close parentheses squared end cell equals cell open parentheses square root of open parentheses negative 1 third X squared plus 100 over 3 close parentheses end root close parentheses squared end cell row cell X squared minus 4 X plus 4 end cell equals cell negative 1 third X squared plus 100 over 3 end cell row cell 3 X squared minus 12 X plus 12 end cell equals cell negative X squared plus 100 end cell row cell 4 X squared minus 12 X minus 88 end cell equals 0 row cell X squared minus 3 X minus 22 end cell equals 0 end table

  • Selesaikan persamaan kuadrat straight a x squared plus straight b x plus straight c equals 0 dengan rumus kuadratik yaitu X subscript 1 comma 2 end subscript equals fraction numerator negative straight b plus-or-minus square root of straight b squared minus 4 ac end root over denominator 2 straight a end fraction

table attributes columnalign right center left columnspacing 0px end attributes row cell X subscript 1 comma 2 end subscript end cell equals cell fraction numerator negative left parenthesis negative 3 right parenthesis plus-or-minus square root of left parenthesis negative 3 right parenthesis squared minus 4 open parentheses 1 close parentheses open parentheses negative 22 close parentheses end root over denominator 2 left parenthesis 1 right parenthesis end fraction end cell row blank equals cell fraction numerator 3 plus-or-minus square root of 9 plus 88 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 3 plus-or-minus square root of 97 over denominator 2 end fraction end cell end table

Didapatkan X subscript 1 equals fraction numerator 3 plus square root of 97 over denominator 2 end fraction space dan space X subscript 2 equals fraction numerator 3 minus square root of 97 over denominator 2 end fraction

  • Subtitusikan masing-masing  X subscript 1 space dan space X subscript 2 ke persamaan Y equals 40 minus X squared

untuk X subscript 1 equals fraction numerator 3 plus square root of 97 over denominator 2 end fraction maka 

Y subscript 1 equals 40 minus open parentheses fraction numerator 3 plus square root of 97 over denominator 2 end fraction close parentheses squared Y subscript 1 equals fraction numerator 27 minus 3 square root of 97 over denominator 2 end fraction

untuk X subscript 2 equals fraction numerator 3 minus square root of 97 over denominator 2 end fraction maka

Y subscript 2 equals 40 minus open parentheses fraction numerator 3 minus square root of 97 over denominator 2 end fraction close parentheses squared Y subscript 2 equals fraction numerator 27 plus 3 square root of 97 over denominator 2 end fraction

Jadi, titik potong antara kedua persamaan tersebut adalah 

open parentheses fraction numerator 3 plus square root of 97 over denominator 2 end fraction comma fraction numerator 27 minus 3 square root of 97 over denominator 2 end fraction close parentheses space dan space open parentheses fraction numerator 3 minus square root of 97 over denominator 2 end fraction comma fraction numerator 27 plus 3 square root of 97 over denominator 2 end fraction close parentheses

 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

838

Iklan

Pertanyaan serupa

Tentukan daerah asal dari fungsi berikut. a. f ( x ) = x − 1 ​

1

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia