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Diketahui 1,7 gram gas dilarutkan dalam 1 liter air. Kemudian, ke dalam larutan tersebut ditambahkan 2,675 gram . Jika ,  , dan   = ,pH campuran tersebut adalah ....

Pertanyaan

Diketahui 1,7 gram gas begin mathsize 14px style N H subscript 3 end style dilarutkan dalam 1 liter air. Kemudian, ke dalam larutan tersebut ditambahkan 2,675 gram begin mathsize 14px style N H subscript 4 Cl end style. Jika begin mathsize 14px style K subscript b space N H subscript 3 equals 2 cross times 10 to the power of negative sign 5 end exponent end style,  begin mathsize 14px style M subscript r space N H subscript 3 equals 17 space g space mol to the power of negative sign 1 end exponent end style, dan begin mathsize 14px style M subscript r end style undefined = begin mathsize 14px style 53 comma 5 space g space mol to the power of minus sign end style,pH campuran tersebut adalah .... 

  1. begin mathsize 14px style 5 minus sign log space 4 end style 

  2. begin mathsize 14px style 6 minus sign log space 3 end style 

  3. begin mathsize 14px style 8 plus log space 3 end style 

  4. begin mathsize 14px style 9 plus log space 4 end style 

  5. begin mathsize 14px style 10 plus log space 4 end style 

Pembahasan Soal:

Reaksi antara begin mathsize 14px style N H subscript 3 end style dengan begin mathsize 14px style N H subscript 4 Cl end style merupakan larutan penyangga dengan undefined sebagai asam lemah dan undefined sebagai garam asam konjugasi.


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell massa space N H subscript 3 end cell equals cell 1 comma 7 space gr end cell row cell massa space N H subscript 4 Cl end cell equals cell 2 comma 675 space gr end cell row cell K subscript b space N H subscript 3 end cell equals cell 2 cross times 10 to the power of negative sign 5 end exponent end cell row cell Mr space N H subscript 3 end cell equals cell 17 space gr space mol to the power of negative sign 1 end exponent end cell row cell Mr space N H subscript 4 Cl end cell equals cell 53 comma 5 space g space mol to the power of negative sign 1 end exponent end cell row blank blank blank row cell mol space N H subscript 3 end cell equals cell gr over Mr end cell row blank equals cell fraction numerator 1 comma 7 space gr over denominator 17 space gr space mol to the power of negative sign 1 end exponent end fraction end cell row blank equals cell 0 comma 1 space mol end cell row blank blank blank row cell mol space N H subscript 4 Cl end cell equals cell gr over Mr end cell row blank equals cell fraction numerator 2 comma 675 space gr over denominator 53 comma 5 space gr space mol to the power of negative sign 1 end exponent end fraction end cell row blank equals cell 0 comma 05 space mol end cell row blank blank blank row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript b cross times fraction numerator mol space N H subscript 3 over denominator mol space N H subscript 4 Cl end fraction end cell row blank equals cell left parenthesis 2 cross times 10 to the power of negative sign 5 end exponent right parenthesis cross times fraction numerator 0 comma 1 space mol over denominator 0 comma 05 space mol end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 5 end exponent end cell row blank blank blank row pOH equals cell negative sign log space 4 cross times 10 to the power of negative sign 5 end exponent end cell row blank equals cell 5 minus sign log space 4 end cell row pH equals cell 14 minus sign left parenthesis 5 minus sign log space 4 right parenthesis end cell row blank equals cell 10 plus log space 4 end cell end table end style


pH larutan campuran adalah 10 + log 4.

Jadi, jawaban yang benar adalah E.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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