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Pertanyaan

Diberikan vektor a = ⎝ ⎛ ​ p 2 − 1 ​ ⎠ ⎞ ​ , b = ⎝ ⎛ ​ 4 − 3 6 ​ ⎠ ⎞ ​ , dan c = ⎝ ⎛ ​ 2 − 1 3 ​ ⎠ ⎞ ​ . Jika vektor a tegak lurus vektor b , maka hasil dari ( a − b ) ⋅ ( 2 c ) adalah ....

Diberikan vektor . Jika vektor  tegak lurus vektor , maka hasil dari adalah ....

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F. Nur

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

hasil dari adalah .

 hasil dari begin mathsize 14px style open parentheses a with rightwards arrow on top minus b with rightwards arrow on top close parentheses times open parentheses 2 c with rightwards arrow on top close parentheses end style adalah begin mathsize 14px style negative 56 end style.

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Pembahasan

Jika vektor tegak lurus vektor , maka Sehingga vektor Menentukanhasil dari Jadi,hasil dari adalah .

Jika vektor begin mathsize 14px style a with rightwards arrow on top end style tegak lurus vektor begin mathsize 14px style b with rightwards arrow on top end style, maka begin mathsize 14px style a with rightwards arrow on top times b with rightwards arrow on top equals 0 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a with rightwards arrow on top times b with rightwards arrow on top end cell equals 0 row cell open parentheses table row p row 2 row cell negative 1 end cell end table close parentheses times open parentheses table row 4 row cell negative 3 end cell row 6 end table close parentheses end cell equals 0 row cell 4 p plus 2 open parentheses negative 3 close parentheses plus open parentheses negative 1 close parentheses open parentheses 6 close parentheses end cell equals 0 row cell 4 p minus 6 minus 6 end cell equals 0 row cell 4 p minus 12 end cell equals 0 row cell 4 p end cell equals 12 row p equals 3 end table end style 

Sehingga vektor begin mathsize 14px style a with rightwards arrow on top equals open parentheses table row 3 row 2 row cell negative 1 end cell end table close parentheses end style

Menentukan hasil dari begin mathsize 14px style open parentheses a with rightwards arrow on top minus b with rightwards arrow on top close parentheses times open parentheses 2 c with rightwards arrow on top close parentheses end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses a with rightwards arrow on top minus b with rightwards arrow on top close parentheses times open parentheses 2 c with rightwards arrow on top close parentheses end cell equals cell open parentheses open parentheses table row 3 row 2 row cell negative 1 end cell end table close parentheses minus open parentheses table row 4 row cell negative 3 end cell row 6 end table close parentheses close parentheses times open parentheses 2 open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses close parentheses end cell row blank equals cell open parentheses table row cell negative 1 end cell row 5 row cell negative 7 end cell end table close parentheses times open parentheses table row 4 row cell negative 2 end cell row 6 end table close parentheses end cell row blank equals cell open parentheses negative 1 close parentheses open parentheses 4 close parentheses plus 5 open parentheses negative 2 close parentheses plus open parentheses negative 7 close parentheses open parentheses 6 close parentheses end cell row blank equals cell negative 4 plus open parentheses negative 10 close parentheses plus open parentheses negative 42 close parentheses end cell row blank equals cell negative 56 end cell end table end style 

Jadi, hasil dari begin mathsize 14px style open parentheses a with rightwards arrow on top minus b with rightwards arrow on top close parentheses times open parentheses 2 c with rightwards arrow on top close parentheses end style adalah begin mathsize 14px style negative 56 end style.

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Diketahui vektor a = 3 i − 4 j ​ + 2 k dan b = 2 i + 3 j ​ serta c = 4 i + j ​ − 6 k , maka hasil dari 2 a ( 3 b − 2 c ) = ....

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