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Diberikan data: OF 2 ​ ( g ) + H 2 ​ O ( l ) → O 2 ​ ( g ) + 2 HF △ H = − 318 kJ SF 4 ​ ( g ) + 2 H 2 ​ O ( l ) → SO 2 ​ ( g ) + 4 HF △ H = − 828 kJ S ( s ) + O 2 ​ ( l ) → SO 2 ​ ( g ) △ H = − 297 kJ Nilai △ H untuk reaksi: 2 S ( s ) + 2 OF 2 ​ ( g ) → SO 2 ​ ( g ) + SF 4 ​ ( g ) adalah ...

Diberikan data:

Nilai  untuk reaksi:

 

adalah ...

  1. +2058 kJspace 

  2. -2058 kJspace 

  3. -402 kJspace 

  4. +402 kJspace 

  5. -1443 kJspace 

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Q. 'Ainillana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

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Pembahasan

Opsi yang tepat adalah C.-402 kJ Pada soal di atas diketahui nilai △ H beberapa reaksi, untuk mencari △ H reaksi yang diminta, maka dengan mengunakan penentuan entalpi pembentukan dari reaksi yang telah disajikan. Maka reaksi di atas menjadi: Mengeliminasi dua senyawa yang sama apabila berseberangan dengan tanda panah Maka nilai △ H reaksi tersebut adalah -402 kJ

Opsi yang tepat adalah C. -402 kJ


Pada soal di atas diketahui nilai  beberapa reaksi, untuk mencari  reaksi yang diminta, maka dengan mengunakan penentuan entalpi pembentukan dari reaksi yang telah disajikan.

OF subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript rightwards arrow straight O subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus 2 HF space space space space space space space space space space space space space space space space space increment straight H equals negative 318 space kJ space left parenthesis tetap cross times 2 right parenthesis SF subscript 4 space left parenthesis straight g right parenthesis end subscript plus 2 straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript rightwards arrow SO subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus 4 HF space space space space space space space space space space space space space space increment straight H equals negative 828 space kJ space left parenthesis dibalik cross times 2 right parenthesis straight S subscript open parentheses straight s close parentheses end subscript plus straight O subscript begin italic style straight 2 straight space left parenthesis l right parenthesis end style end subscript rightwards arrow SO subscript 2 space italic left parenthesis straight g italic right parenthesis end subscript space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space increment straight H equals negative 297 space kJ space left parenthesis tetap cross times 2 right parenthesis  

Maka  reaksi di atas menjadi:

2 OF subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus 2 straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript rightwards arrow 2 straight O subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus 4 HF space space space space space space space space space space space space space space space space space increment straight H equals negative 318 space kJ space left parenthesis tetap cross times 2 right parenthesis S O subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus 4 HF rightwards arrow SF subscript 4 space left parenthesis straight g right parenthesis end subscript plus 2 straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript space space space space space space space space space space space space space space space space space space space space increment straight H equals negative 828 space kJ space left parenthesis dibalik cross times 1 right parenthesis 2 straight S subscript open parentheses straight s close parentheses end subscript plus 2 straight O subscript begin italic style straight 2 straight space left parenthesis l right parenthesis end style end subscript rightwards arrow 2 SO subscript 2 space italic left parenthesis straight g italic right parenthesis end subscript space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space increment straight H equals negative 297 space kJ space left parenthesis tetap cross times 2 right parenthesis  

Mengeliminasi dua senyawa yang sama apabila berseberangan dengan tanda panah

2 OF subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus up diagonal strike 2 straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript end strike rightwards arrow up diagonal strike 2 straight O subscript 2 space italic left parenthesis g italic right parenthesis end subscript end strike plus up diagonal strike 4 HF end strike space space space space space space space space space space space space space space space space space increment straight H equals negative 318 space kJ space left parenthesis tetap cross times 2 right parenthesis up diagonal strike S O subscript 2 space italic left parenthesis g italic right parenthesis end subscript end strike plus up diagonal strike 4 HF end strike rightwards arrow SF subscript 4 space left parenthesis straight g right parenthesis end subscript plus up diagonal strike 2 straight H subscript 2 straight O subscript begin italic style left parenthesis l right parenthesis end style end subscript end strike space space space space space space space space space space space space space space space space space space space space increment straight H equals negative 828 space kJ space left parenthesis dibalik cross times 1 right parenthesis bottom enclose 2 straight S subscript open parentheses straight s close parentheses end subscript plus up diagonal strike italic 2 O subscript begin italic style straight 2 straight space left parenthesis l right parenthesis end style end subscript end strike rightwards arrow up diagonal strike 2 SO subscript 2 space italic left parenthesis straight g italic right parenthesis end subscript space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space increment straight H equals negative 297 space kJ space left parenthesis tetap cross times 2 right parenthesis end enclose 2 straight S subscript open parentheses s close parentheses end subscript plus 2 OF subscript begin italic style straight 2 straight space left parenthesis g right parenthesis end style end subscript rightwards arrow SO subscript 2 space italic left parenthesis g italic right parenthesis end subscript plus SF subscript 4 space open parentheses g close parentheses end subscript space space space space space space space space space space space space space space space space space space increment straight H equals negative 402 space kJ space  

Maka nilai  reaksi tersebut adalah -402 kJ

 

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