Iklan

Pertanyaan

Determinan matriks P yang memenuhi dengan ad ≠ bc adalah ....

Determinan matriks P  yang memenuhi begin mathsize 14px style P open parentheses table row a b row c d end table close parentheses equals open parentheses table row a b row cell negative a plus c end cell cell negative b plus d end cell end table close parentheses end style dengan ad ≠ bc  adalah ....

  1. -1

  2. 0

  3. 1

  4. 2ad-2bc

  5. 2bc-2ad  

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

11

:

15

:

25

Klaim

Iklan

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell det invisible function application open parentheses P open parentheses table row a b row c d end table close parentheses close parentheses end cell equals cell det invisible function application open parentheses table row a b row cell negative a plus c end cell cell negative b plus d end cell end table close parentheses end cell row cell det invisible function application P cross times det invisible function application open parentheses table row a b row c d end table close parentheses end cell equals cell det invisible function application open parentheses table row a b row cell negative a plus c end cell cell negative b plus d end cell end table close parentheses end cell row cell det invisible function application P cross times open parentheses a times d minus b times c close parentheses end cell equals cell open parentheses a times open parentheses negative b plus d close parentheses minus b times open parentheses negative a plus c close parentheses close parentheses end cell row cell det invisible function application P cross times open parentheses a d minus b c close parentheses end cell equals cell open parentheses negative a b plus a d plus a b minus b c close parentheses end cell row cell det invisible function application P cross times open parentheses a d minus b c close parentheses end cell equals cell open parentheses a d minus b c close parentheses semicolon a d not equal to b c end cell row cell det invisible function application P end cell equals cell fraction numerator a d minus b c over denominator a d minus b c end fraction end cell row cell det invisible function application P end cell equals 1 end table end style 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

7

diyana

Bantu banget

Iklan

Pertanyaan serupa

Jika dan det A =-2, maka d e tB A − 1 = ....

4

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia